-0.8662866239 . . . is:
1 answer:
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Answer:
Step-by-step explanation:
Given :
...................... equation 1
........................ equation 2
solving the system of linear equation by substitution method , substitute equation 1 into equation 2 , that is
collect the like terms
therefore :
substitute into equation 1 to find the value of y , that is
Therefore :
Answer:
P(Z < 2.37) = 0.9911.
Step-by-step explanation:
We are given that Let z denote a random variable that has a standard normal distribution.
Let Z = a random variable
So, Z ~ Standard Normal(0, 1)
As we know that the standard normal distribution has a mean of 0 and variance equal to 1.
Z = ~ N(0,1)
where, = mean = 0
= standard deviation = 1
Now, the probability that z has a value less than 2.37 is given by = P(Z < 2.37)
P(Z < 2.37) = P(Z < ) = P(Z < 2.37) = 0.9911
The above probability is calculated by looking at the value of x = 2.37 in the z table which has an area of 0.9911.