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3 years ago

What is the unite rate?

Mathematics

2 answers:

Anit [1.1K]3 years ago

7 0

Answer: 60baskets

Step-by-step explanation:

bazaltina [42]3 years ago

5 0

Answer:

A unit rate is a rate where the second quantity is one unit , such as $34 per pound, 25 miles per hour, 15 Indian Rupees per Brazilian Real, etc. 1 minute=60 seconds1 hour=60 minutes (or) 3600 seconds1 day=24 hours (or) 1440 minutes.

Step-by-step explanation:

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3 years ago

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Drag each tile to the correct box consider the given functions f,g and h place the tiles in order from least to greatest accordi

Alja [10]

Answer:

Step-by-step explanation:

By definition, the average rate of change of a function f over an interval [a,b] is given by

$\dfrac{f(b)-f(a)}{b-a}$

compute the quantity

$\dfrac{f(3)-f(0)}{3}$

for all the three function

Average rate of change of f:

We will simply use the table to check the values for f(3) and f(0):

$\dfrac{f(3)-f(0)}{3}=\dfrac{10-1}{3} = 3$

Average rate of change of g:

We will use the graph to to check the values for g(3) and g(0):

$\dfrac{g(3)-g(0)}{3}=\dfrac{8-1}{3} = \dfrac{7}{3}$

Average rate of change of h:

We can plug the values in the equation to get h(3) and h(0):

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And so the average rate of change is

$\dfrac{h(3)-h(0)}{3}=\dfrac{6-(-6)}{3} = 4$

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3 years ago

Community Gym charges a $60 membership fee and a $55 monthly fee. Workout Gym charges a $200 membership fee and a $45 monthly fe

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Answer:

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Step-by-step explanation:

60 + 55m = ?

200 + 45m = ?

60 + 55 = 115 + 55 = 170 + 55 = 225 + 55 = 280

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3 years ago

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3 years ago

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Answer:

The value of the test statistic is 4.70.

Step-by-step explanation:

The hypothesis for this test can be defined as follows:

H₀: Men do not spend more than women on St. Patrick's day, i.e. μ₁ = μ₂.

Hₐ: Men spend more than women on St. Patrick's day, i.e. μ₁ > μ₂.

The population standard deviations are not known.

So a t-distribution will be used to perform the test.

The test statistic for the test of difference between mean is:

$t=\frac{\bar x_{1}-\bar x_{2}}{\sqrt{\frac{s^{2}_{1}}{n_{1}}+\frac{s^{2}_{2}}{n_{2}}} }$

Given:

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Compute the value of the test statistic as follows:

$t=\frac{\bar x_{1}-\bar x_{2}}{\sqrt{\frac{s^{2}_{1}}{n_{1}}+\frac{s^{2}_{2}}{n_{2}}} }=\frac{55-44}{\sqrt{\frac{15^{2}}{90}+\frac{16^{2}}{86} }}=4.70$

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3 years ago