Evolution or Natural Selection fam ;)
If all else fails, moms spaghetti
The choices are:
<span>A. Matrix protein
B. Hemagglutinin
C. An ion channel
D. Neuraminidase
</span>
The right answer is B. Hemaglutinin
Explanation:
Haemagglutinins are triangular rods. They allow the attachment of Influenzaviruses on the target cells of the respiratory tree. In the presence of red blood cells, a haemagglutination (liquid medium) is obtained.
<u>About the other components of Influenza virus:</u>Neuraminidase is a mushroom-shaped spike composed of a tetramer consisting of 4 subunits of a single glycoprotein. At 37 ° C, the neuraminidase destroys the bonds (virus - cells) and thus allows the release of neoformed virions in the external environment: it is elution.
The membrane protein M and the protein subunits of the nucleocapsid are antigenic and are the basis of the classification of Influenzavirus types A, B and C. They induce the synthesis of non-protective antibodies fixing the complement.
1.) Follow the rules and laws in place which are meant to protect us.
2.) Alert the proper authorities when you know someone is not following the laws in place to protect us.
3.) If you see someone in danger help them however you can.
4.) Create a community watch group to prevent crime and ensure safety of those around us.
5.) Have a free social distancing neighborhood workout group to keep people active during quarantine.
Answer/ Explanation:
a. The genotype of a homozygous white eyed long winged female would be Vg+Vg+XrXr. We denote the white allele as recessive (r) because the XY male only has one copy and yet has red eyes, so the red eye trait (R) must be dominant. A homozygous red eyed vestigial winged male would have be VgVgXRY. The possible gametes for the female are Vg+Xr only. For the male, the possible gametes are VgXR or VgY
The attached punnett square shows the results of the cross. The females will all be Vg+VgXRXr. The males will all be Vg+VgXRY (must inherit Y from father). That means they will all have normal length wings, the males will have white eyes and the females will have red eyes.
b. The F2 flies arise from intercrossing the F1, so the cross will be Vg+VgXRXr x Vg+VgXRY. The possible gametes for the mother are: Vg+XR, Vg+Xr, VgXR or VgXr. The possible gametes for the father are Vg+Xr
, Vg+Y
, VgXr
, VgY
. The attached punnet square shows this cross. The ratio of the phenotypes will be 6:6:2:2, or 3:3:1:1 (long-winged red eye: long-winged white eye: vestigial wing red eye: vestigial wing white eye), genotypes shown in the attachment.
c. F1 cross back to the mother would be Vg+VgXRY x Vg+Vg+XrXr. The genotypes are shown in the attached punnet square. The offspring will all be long-winged with white eyes. The F1 to the father would be Vg+VgXRXr x VgVgXRY. The ratio would be 3:3:1:1 long-winged red eye: long-winged white eye: vestigial wing red eye: vestigial wing white eye
Answer:
It takes 27 days, 7 hours, and 43 minutes for our Moon to complete one full orbit around Earth. This is called the sidereal month, and is measured by our Moon's position relative to distant “fixed” stars. However, it takes our Moon about 29.5 days to complete one cycle of phases (from new Moon to new Moon).
The 27th, I believe
Explanation:
