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Finger [1]
3 years ago
11

Question 7 of 10

Mathematics
1 answer:
xeze [42]3 years ago
5 0

Answer:40

Step-by-step explanation:

there are 6 triangles / 2= 3,add that tothe squares(37) = 40

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What is the center and radius of a circle with the equation: (x-25)^2 + (y+17)^2 = 361
vovikov84 [41]

Answer:

centre=(25,-17)

radius=19

Step-by-step explanation:

comparing with the formula

(x-h)^2+( y-k)^2=r^2

5 0
4 years ago
Tanner has 80$ in an savings account. The interest rate is 10% and is not compounded. How much interest will he earn in 1 year?
Verizon [17]

Answer:

$8

Step-by-step explanation:

The formula for simple interest is i = p*r*t, where r is the interest rate as a decimal fraction.

Here, i = $80*0.10*1 = $8

4 0
3 years ago
Find the value of x a. 2x=1/4 b. 4x=  -1/10
yKpoI14uk [10]
A. x=1/8
b. x=0.025 same thing, just divide<span />
3 0
3 years ago
Read 2 more answers
A storeowner mixed 8 pounds of peanuts and 5 pounds of M&amp;M's. This 13 pound mixture sold for $55.27. A second mixture includ
olga2289 [7]
<span>Let P be the cost per pound of peanuts. Let M be the cost per pound of M&M's. We can set up two equations to solve this question. (1) 8P + 5M = 55.27 (2) 6P + 4M = 42.70 Let's multiply equation (1) by 3. Let's multiply equation (2) by 4. (1) 24P + 15M = 165.81 (2) 24P + 16M = 170.80 Let's subtract equation (1) from equation (2). M = 4.99 Let's put M = 4.99 in equation (2) to find P. 6P + 4(4.99) = 42.70 6P = 42.70 - 19.96 6P = 22.74 P = 22.74 / 6 P = 3.79 The cost per pound of peanuts is $3.79 The cost per pound of M&M's is $4.99</span>
6 0
3 years ago
A rational number raised to a rational power can either be rational or irrational. For example, 4^( 1/ 2) is rational because 4
Lady bird [3.3K]

Answer:

Step-bThis is an interesting problem. To solve it I should find two irrational numbers r and s such that rs is rational.

I am not sure I am able to do that. However, I am confident that the following argument does solve the problem.

As we know, √2 is irrational. In particular, √2 is real and also positive. Then √2√2 is also real. Which means that it is either rational or irrational.

If it's rational, the problem is solved with r = √2 and s = √2.

Assume √2√2 is irrational. Let r = √2√2 and s = √2. Then rs = (√2√2)√2 = √2√22 = √22 = 2. Which is clearly rational.

Either way, we have a pair of irrational numbers r and s such that rs is rational. Or do we? If we do, which is that?

(There's an interesting related problem.)

Chris Reineke came up with an additional example. This one is more direct and constructive. Both log(4) and √10 are irrational. However

√10 log(4) = 10log(2) = 2.y-step explanation:

7 0
3 years ago
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