It is definitely not equal to it. It's greater.
Question 1:
Slope = 1/5
y = mx + c
y = 1/5 x + c
at point (5, -1)
-1 = 1/5 (5) + c
- 1= 1 + c
c = - 2
y = 1/5x - 2
5y = x - 10
Question 2:
slope = (9-5)/(3-1)
Slope = 2
y = mx + c
y = 2x + c
at point (1, 5)
5 = 2(1) + c
c = 5 - 2
c = 3
y = 2x + 3
4x - 2 = 2x + 8
2x -2 = 8
2x = 10
x = 5
4(5)-2 = 2(5)+8
20-2 = 10+8
18 = 18
Answer:
D
Step-by-step explanation:
The augmented matrix for the system of three equaitons is
Multiply the first row by 5, the second row by -3 and add these two rows:
Subtract the third row from the second:
Divide the third row by 6:
Now multiply the third equation by 26 and add it to the second row:
You get the system of three equations:
From the third equation
Substitute z=2 into the second equation:
Now substitute z=2 and y=5 into the first equation:
The solution is (1,5,2)
4 days spending equal amounts so if x is how much he spends per day and y is the original amount then 4x=1/5y bc he has 4/5 left meaning what he spent was 1/5 of the original and after 10 more days which was 14 total he spent all but 30 so the total minus 30 will be how much kyle spent so
14x=y-30 which is y=(14x+30) and substitute that in for y in 4x=1/5y so 4x=1/5 (14x+30)
20x=14x+30
6x=30
x=5 and plug that in either of the original equations 4(5)=1/5y
y=100
so he had $100 and spent $5 per day