P=2(L+W) and P=34 so
2(L+W)=34
L+W=17 so we can say
L=17-W
A=LW using L from above
A=(17-W)W
A=17W-W^2 and A=30 so
30=17W-W^2
W^2-17W+30=0
W^2-2W-15W+30=0
W(W-2)-15(W-2)=0
(W-15)(W-2)=0
So the dimensions of the rectangle are 15 meters by 2 meters.
1) Perimeter=2length+2width
This is the formula for finding the perimeter of a rectangle
2) Density=mass/volume
The “Quotient” is the answer to a division problem (like how the “sum” is the answer to an addition problem) which is why we know to divide mass and volume
3) Force = mass*acceleration
The “product” is the answer to a multiplication problem which is why we know to multiply mass and acceleration
4) surface area = 6*L^2
The formula used to calculate the area of a square is L^2. The problem tells us that surface area is the sum of all the faces of a 3D shape. Because there are 6 sides on a cube, we multiply L^2 by 6.
Hope this helps!
Answer:
how would you classify this triangle? remember you need two names.
The surface area would be 68 squared inches. I hope this helps!
