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sergeinik [125]
3 years ago
9

Please help :/ ill give brainlly -.-

Mathematics
2 answers:
Olin [163]3 years ago
8 0

Answer:

2 50 mL bottles

Step-by-step explanation:

Find the cost per mL

55 / 80 mL =.6875 per mL

Now find the price of the buy one get one 1/2 off

45 + 1/2 (45) = 45+22.5=67.5

That will be for 50+50 mL

67.5 /100 ml =.675 per mL

The 100 mL is a better deal

LuckyWell [14K]3 years ago
8 0

Answer:

Two 50 ml bottles.

Step-by-step explanation:

The 80 ml bottle costs £55. That means that you have to pay £55 / 80 per ml of perfume, which is £0.6875.

On the other hand, the 50 ml bottles cost £45. Since it is buy one get one half off, you can do 1.5 * £45 to get the price of both bottles. That would be £67.5 for 100 ml of perfume. You would pay £67.5 / 100 per ml of perfume, which is £0.675.

It is cheaper to get two bottles of 50 ml perfume, so that is the best value for the money.

Hope this helps!

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Teresa earned scores of 88, 84, 88 points and 91 points on 4 test what is the lowest score she can get on the fifth test and sti
Usimov [2.4K]

Answer:

99 points

Step-by-step explanation:

Average of a data a is the sum of the data divided by the number of data.

Average = sum of data ÷ number of data

A = T/n .....1

For the average of 5 test to be 90.

The total sum of score must be;

Number of tests n = 5

Average A = 90

Substituting into equation 1

90 = T/5

T = 90×5 = 450 points

The total score must be equal to 450 point to have an average of 90 points

The sum of the first four test is;

88+84+88+91 = 351

Let x represent the first score,

351 + x = 450

x = 450 - 351

x = 99 points

The minimum score she can get in the fifth test is 99 points

5 0
3 years ago
Which relation is not a function?
Lelu [443]

The Answer is A.

Repeating number is not a function. It's ok to have repeating number in Y or the range but not the X which is the Domain.

4 0
3 years ago
Please help me, its due today
nasty-shy [4]

Answer:

No, u keep going around and answering questions with sorry i don't know the answer and its pising me off, so just stop before you get your account reported too many times and end up getting banned from answering questions.

7 0
3 years ago
stion 1 OT 5A researcher recorded the number of swans and the number of ducks in a lake every month. Function s represents the n
Anon25 [30]

Given functions are

s(n)=2(1.1)^n+5_{}d(n)=4(1.08)^n+3

The total number of ducks and swans in the lake after n months can be determined by adding the functions s(n) and d(n).

t(n)=s(n)+d(n)

t(n)=(2(1.1)^n^{}+5)+(4(1.08)^n+3)

t(n)=2(1.1)^n+5+4(1.08)^n+3

t(n)=2(1.1)^n+4(1.08)^n+5+3

t(n)=2(1.1)^n+4(1.08)^n+8

Taking 2 as common, we get

t(n)=2\lbrack(1.1)^n+2(1.08)^n+4\rbrack

Hence The total number of ducks and swans in the lake after n months is

t(n)=2\lbrack(1.1)^n+2(1.08)^n+4\rbrack

8 0
1 year ago
The sample size needed to estimate the difference between two population proportions to within a margin of error E with a signif
devlian [24]

Answer:

n= (z)22E2

n=10× 99%÷ 0.07

3 0
2 years ago
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