Please help ASAP!

Mathematics

1 answer:

Lana71 [14]4 years ago

8 0

1)x+1) has positive slope, it is only A or B
2) For f(x)=4 we have x≥1, so this graph should begin with black dot.
3)So answer is B
Blue dot should be empty.
Orange dot should be black.

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Please help fast, I will give brainliest to whoever does

Harlamova29_29 [7]

Answer:

Ok so first, divide the figure into 2 triangles ABC and ADC

Then, find the area of triangle ABC, base being 10 (5+5) and height being 4

= 1/2 * bh

= 1/2 * 10 * 4

= 20 sq. units

For 2 triangles, 20 * 2 = 40 sq. units

3 0

3 years ago

Read 2 more answers

The graph shows two lines, A and B.

muminat

Ur 1 solution is where the lines intersect, which is (1,4)

7 0

3 years ago

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Enter the values for the variables that give the correct simplified expressions, x = ≥ 0.

ELEN [110]

Answer:

b= 2x²; c = 4; 3 = 3 ; g = 6x

Step-by-step explanation:

$\textbf{(1)}\\\sqrt{50{x}^{2} } = \sqrt{25\times2x^{2}} = 5\times \mathbf{\sqrt{2x^{2}}}\\\textbf{b = 2x}^{2}\\\\\textbf{(2)}\\\sqrt{32x} = \sqrt{16 \times 2x} = \mathbf{4}\times \sqrt{2x}\\\textbf{c = 4}\\\\\textbf{(3)}\\\sqrt{18n} = \sqrt{9 \times 2n} = \mathbf{3}\times \sqrt{2n}\\\textbf{e = 3}\\\\\textbf{(4)}\\\sqrt{72x^{2}} = \sqrt{36 \times 2x^{2}} = 6\times \sqrt{2} \times x\\= \mathbf{6x}\sqrt{2}\\\textbf{g = 6x}$