We consider the x- and y-coordinates separately. Let the coordinates of G be (x, y). Now considering the x-coordinates:
FG/FH = (x - (-3)) / (-3 - (-3)) = 2/3
x + 3 = (2/3)(6)
x = 1
For the y-coordinates:
FG/FH = (y - 2) / (7 - 2) = 2/3
y - 2 = (2/3)(5)
y = 16/3
Therefore the coordinates of G are (1, 16/3).
Answer:
B
Step-by-step explanation:
6 ^ -7
Answer:
19.
Step-by-step explanation:
PEMDAS.
3^2=9
5 x 2 + 9
10 + 9 = 19
Switch where the x and y are, then solve for y. f(x) = y.
x = 3y^2 + 6
x-6 = 3y^2
(x-6)/3 = y^2
f^-1(x) = y = sqrt((x-6)/3)
Answer:
happy birth day to me
Step-by-step explanation:
its F was i close
