Answer:
The angles of a parallelogram are 135°-45°-135°-45°
Step-by-step explanation:
we know that
In a parallelogram opposites angles are congruent and consecutive angles are supplementary
Remember that
The sum of a exterior angle and its interior angle is equal to 180 degrees
Let
x ----> the measure of one interior angle of parallelogram
y ----> the measure of the other interior angle of parallelogram
we have that
solve for x
<em>Find the measure of the other interior angle of parallelogram</em>
Remember that consecutive interior angles are supplementary
substitute the value of x
solve for y
therefore
The angles of a parallelogram are 135°-45°-135°-45°
Answer:
Question 2 the answer is C) y = -3/2x + 2
Question 3 the answer is D) x = 4
Step-by-step explanation:
To solve either we first need to know that parallel lines have the same slope.
So in #2 we know that the new line will also have a slope of -3/2. Therefore, we can use that along with the point given in the problem in point-slope form to get the new equation.
y - y1 = m(x - x1)
y + 1 = -3/2(x - 2)
y + 1 = -3/2x + 3
y = -3/2x + 2
And for #3, we know that we have a vertical line due to the fact that it is expressed as x = a number. Therefore, we must have the same in the answer. D is the only one that has such an answer.
<h3>
Answer: y - 4 = -2(x - 5)</h3>
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Explanation:
Point slope form is
y - y1 = m(x - x1)
where m is the slope and (x1,y1) is the point the line goes through.
Parallel lines have equal slopes but different y intercepts. The given equation y = -2x-3 has a slope of -2, meaning that m = -2 is also the slope of the mystery parallel line.
-2 will go in the second box that's just to the left of the parenthesis.
The coordinates of (5, 4) will go in the other remaining boxes to finish off the equation.
We go from this
y - y1 = m(x - x1)
to this
y - 4 = -2(x - 5)
Answer:
А.The system has two solutions, but only one is viable because the other results in a negative width.
Step-by-step explanation:
Given
Let:
length of play area A
width of play area A
length of play area B
width of play area B
Area of A
Area of B
From the question, we have the following:
The area of A is:
This gives:
Open bracket
The area of B is:
Substitute:
Open brackets
Expand
We have that:
This gives:
Collect like terms
Using quadratic calculator, we have:
or 
--- approximated
But the width can not be negative; So:
Answer:
Step-by-step explanation:
2s + t = r
t = r - 2s
