The matching forms of the numbers are as represented below upon evaluation;
- -(-75) = 75
- -(87) = -87
- -(20) = -20
- -(-20) = 20
- -(12) = -12
- -(-12) = 12
- -(75) = -75
- -(-87) = 87
<h3>Opening up parenthesis</h3>
The given numbers can be simplified by opening up the parenthesis as indicated above in which case,
- The product of 2 negatives equals a positive sign
- The product of ,a negative and positive equals negative.
Read more on parenthesis;
brainly.com/question/25935638
Using Pythagorean theorem, the student walked 53.58 meters more compared to the total displacement from the starting point.
If a student walks 100 meters north, then 100 meters west, then the path he travels resembles the sides of a right triangle (see attached photo).
Using Pythagorean theorem, we can solve for the total displacement from the starting point to the end point.
c^2 = a^2 + b^2
where c is the total displacement from the starting point to the end point
a is the distance he walks up north
b is the distance he walks to the west
c^2 = 100^2 + 100^2
c^2 = 10,000 + 10,000
c^2 = 20,000
c = 141.42 meters
Comparing the total distance the student walked and the total displacement from the starting point to the end point by subtraction.
100 meters + 100 meters - 141.42 meters = 53.58 meters
Learn more about Pythagorean Theorem here: brainly.com/question/343682
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make them both fractions with the same bottom number
3-7/8 = 31/8
2-1/4 = 9/4 ( need to multiply by 2 to make it match ) so it becomes 18/8
now subtract 2 top numbers 31-18 = 13 so now you have 13/8
8/8=1 so 13-8 = 5 so the answer will be 1 and 5/8
Answer:
118.125 lb
Step-by-step explanation:
0=2.25
H=6.5 x O
H=6.5 x 2.25
H=14.625
H+O=2.25+14.625=16.875 per day
16.875x7 days=118.125 lb
Step-by-step explanation:
<em>cotx-</em><em> </em><em>tanx</em><em>=</em><em> </em><em>2cot2x</em>
<em>L.H.S</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>cosx</em><em>/</em><em>sinx-</em><em> </em><em>sinx</em><em>/</em><em>cosx</em><em> </em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>(</em><em>cos</em><em>²</em><em>x-</em><em> </em><em>sin</em><em>²</em><em>x</em><em>)</em><em>/</em><em> </em><em>sinxcosx</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>[</em><em> </em><em>cos</em><em>²</em><em>x-</em><em>(</em><em>1</em><em>-cos</em><em>²</em><em>x</em><em>)</em><em>]</em><em>/</em><em>sinxcosx</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>(</em><em> </em><em>2cos</em><em>²</em><em>x-1</em><em>)</em><em>/</em><em>sinxcosx</em>
<em> </em><em> </em><em> </em><em>2cosx</em><em>/</em><em> </em><em>2sinxcosx</em>
<em> </em><em> </em><em> </em><em>2cot2x</em>