4,because 2+5 equals to 6 and 4 times one is 4
let "a number" = x
a number is divided by 3 => x/3
14 is added to the quotient => (x/3) + 14
The result is 33 => " = 33"
Solve for x
(x/3) + 14 = 33
Isolate the x. Note the equal sign. What you do to one side you do the other.
Subtract 14 from both sides
(x/3) + 14 (-14) = 33 (-14)
x/3 = 19
Isolate the x. Multiply 3 to both sides
x/3(3) = 19(3)
x = 19(3)
x = 57
57 is your original number
hope this helps
Answer:
A) 6x + 5y = 82
B) 2x + 5y = 54 We'll multiply equation B) by -1
B) -2x -5y = -54 Then we'll add this to A)
A) 6x + 5y = 82
4x = 28
x = 7
y = 8
Step-by-step explanation:
I believe that it is a concurrent power
The reciprocal of 1/5 is 5.
Reciprocals are numbers than when multiplied equal a product of 1. In this question, 1/5 * 5 = 1. An easy trick for finding reciprocals is flipping a fraction.
Hope this helps!!
