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3 years ago

Joan saved $2.34 on an item that is usually $7.89. What percent did she save

Mathematics

1 answer:

xxTIMURxx [149]3 years ago

5 0

(2.34/ 7.89) times 100 = ˜29.65%

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Solve the system of equations. y=x+5 y=-x+7

spin [16.1K]

Answer:

(1,6)

x = 1, y = 6

See attachment for the graph

Step-by-step explanation:

y=x+5

y=-x+7

Using the elimination process

y=x+5

- y=-x+7

----------------

0=2x-2

2=2x

1=x

x=1

Substitute x = 1

y = x + 5

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In ΔUVW, w = 44 cm, u = 83 cm and ∠V=141°. Find the area of ΔUVW, to the nearest square centimeter.

Tema [17]

Answer:

$Area \approx 1149\ cm^2$

Step-by-step explanation:

Given that:

ΔUVW,

Side w = 44 cm, (It is the side opposite to $\angle W$ )

Side u = 83 cm (It is the side opposite to $\angle U$ )

and ∠V=141°

Please refer to the attached image with labeling of the triangle with the dimensions given.

Area of a triangle with two sides given and angle between the two sides can be formulated as:

$A = \dfrac{1}{2}\times a\times b\times sinC$

Where a and b are the two sides and

$\angle C$ is the angle between the sides a and b

Here we have a = w = 44cm

b = u = 44cm

and ∠C= ∠V=141

Putting the values to find the area:

$A = \dfrac{1}{2}\times 44\times 83\times sin141\\\Rightarrow A = \dfrac{1}{2} \times 3652 \times sin141\\\Rightarrow A =1826 \times 0.629\\\Rightarrow A \approx 1149\ cm^2$

So, the area of given triangle to the nearest square centimetre is:

$Area \approx 1149\ cm^2$

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