A = -16 b = 0 c = 541
Use the quadratic formula which is
x = [-b +- sq root (b^2 -4*a*c)] / 2*a
x = [-0 +-sq root (0 -4*-16*541)] / 2 * -16
x = + - sq root (0 -4*-16*541) / -32
x = + - sq root (34,624) / -32
x = + - 186.075 / -32

x1 = 186.075 / -32 = -5.81484375 
x2 = -186.075 / -32 = 5.81484375

7 0

3 years ago

Three less than one-fourth of the product of eight thirds and nine. Please write equation, then solve.

kenny6666 [7]

Put simply, you have to work backwards in making the equations. Start with the product of 8/3 and 9.
$\frac{8}{3}$ *9

Next take 1/4 of that. This can be done in two ways, either multiplying by 1/4:
( $\frac{8}{3}$ *9)* $\frac{1}{4}$

, or dividing everything by 4.
( $\frac{8}{3}$ *9)/4

Finally, subtract three.

The final equation would read:
(( $\frac{8}{3}$ *9)* $\frac{1}{4}$ )-3

Using PE(M/D)(A/S), we'd start with $\frac{8}{3}$ *9

3 and 9 cancel out to be 1 and 3, leaving us with $\frac{8}{1}$ , or 8, and 3 and this part of the equation reading 8*3, which is 24.

The next step is $\frac{24}{4}$ , which is 6.

Lastly we subtract 3 from six, leaving us 3.

7 0

3 years ago

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