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Nutka1998 [239]
3 years ago
14

Early in 2017, Sheryl Crow Equipment Company sold 500 Rollomatics during 2017 at $6,000 each. During 2017, Crow spent $20,000 se

rvicing the 2-year assurance warranties that accompany the Rollomatic. All applicable transactions are on a cash basis.Prepare 2017 entries for Crow assuming that the warranties are not an integral part of the sale (a service-type warranty). Assume that of the sales total, $56,000 relates to sales of warranty contracts. Crow estimates the total cost of servicing the warranties will be $55,000 for 2 years. Estimate revenues to be recognized on a straight-line basis. (If no entry is required, select "No Entry" for the account titles and enter 0 for the amounts. Credit account titles are automatically indented when amount is entered. Do not indent manually. Round intermediate calculations to 5 decimal places, e.g. 1.54657 answers to 0 decimal places, e.g. 5,125.)
Business
1 answer:
sertanlavr [38]3 years ago
3 0

Answer:

Explanation:

                                         Debit $                                   Credit$

a. Cash                3000000  

    Sales revennue (500*6000)                                 3000000

Warranty expenses   55000  

   Estimated warranty liability                                    55000

Estimated warranty liability  20000  

     Cash account                                                    20000

b. Cash account   3000000  

   Sales revenue (500*6000- 56000)                                2944000

   Unearned warranty revenue                                  56000

Warranty expenses   20000  

      Cash account                                                 20000

Unearned warranty revenue  20364  

    Warranty revenue (56000*20000/55000)                      20364

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2.1: A debit is A : a decrease to an account. B : an entry on the left side of an account. C : an entry on the right side of an
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The profit, P, in dollars for manufacturing n units of a certain product is given by the formula P = 3n2 - 90n - 720. (Assume th
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Answer:

n=40

Explanation:

We want to know the value of n when P=480

P=3n^2-90n-720\\480=3n^2-90n-720\\3n^2-90n-720-480=0\\3n^2-90n-1200=0\\3(n^2-30n-400)=0\\n^2-30n-400=0

From here, we can find the factors of the quadratic equation, we need two numbers that multiplied give -400 and added -30. Since they are factors of 400, we can choose -20x20 or -40x10. When adding -20 and 20 the result is zero, but the sum of -40 and 10 is -30. Then:

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n_1=40\\n_2=-10

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n=40

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