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serg [7]
3 years ago
14

the cab charges $1.75 for the flst fee and $0.25 for each mile. write and solve an inequality to determine how many miles eddie

can travel if he his $15 to spend
Mathematics
1 answer:
Dominik [7]3 years ago
6 0

0.25m + 1.75= 15

Move +1.75 to the right side of the equal sign which becomes -1.75

0.25m=15-1.75

subtract 15 and 1.75 which is 13.25

0.25m=13.25

divide 0.25 by both sides. 0.25m divided by 0.25 is 1m and 13.25 divided by 0.25 is 53.

He can travel 53 miles

0.25m + 1.75= 15

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The answer is : 182 million (trust me)
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True or false !!!<br><br> T or F
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3 years ago
Number between 17/4 and V20
Daniel [21]

Answer:

4.485

Step-by-step explanation:

 [divide 17 by 4]

  [  ]

Now, Midpoint of  4.25 and 4.472 =

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Or number between  and  is 4.485.

3 0
3 years ago
770 is 70% of what number?
Andreyy89

Answer:If you are using a calculator, simply enter 770×100÷70, which will give you the answer.

Step-by-step explanation:

3 0
3 years ago
Consider the initial value problem y′+2y=4t,y(0)=8.
Xelga [282]

Answer:

Please read the complete procedure below:

Step-by-step explanation:

You have the following initial value problem:

y'+2y=4t\\\\y(0)=8

a) The algebraic equation obtain by using the Laplace transform is:

L[y']+2L[y]=4L[t]\\\\L[y']=sY(s)-y(0)\ \ \ \ (1)\\\\L[t]=\frac{1}{s^2}\ \ \ \ \ (2)\\\\

next, you replace (1) and (2):

sY(s)-y(0)+2Y(s)=\frac{4}{s^2}\\\\sY(s)+2Y(s)-8=\frac{4}{s^2}  (this is the algebraic equation)

b)

sY(s)+2Y(s)-8=\frac{4}{s^2}\\\\Y(s)[s+2]=\frac{4}{s^2}+8\\\\Y(s)=\frac{4+8s^2}{s^2(s+2)} (this is the solution for Y(s))

c)

y(t)=L^{-1}Y(s)=L^{-1}[\frac{4}{s^2(s+2)}+\frac{8}{s+2}]\\\\=L^{-1}[\frac{4}{s^2(s+2)}]+L^{-1}[\frac{8}{s+2}]\\\\=L^{-1}[\frac{4}{s^2(s+2)}]+8e^{-2t}

To find the inverse Laplace transform of the first term you use partial fractions:

\frac{4}{s^2(s+2)}=\frac{-s+2}{s^2}+\frac{1}{s+2}\\\\=(\frac{-1}{s}+\frac{2}{s^2})+\frac{1}{s+2}

Thus, you have:

y(t)=L^{-1}[\frac{4}{s^2(s+2)}]+8e^{-2t}\\\\y(t)=L^{-1}[\frac{-1}{s}+\frac{2}{s^2}]+L^{-1}[\frac{1}{s+2}]+8e^{-2t}\\\\y(t)=-1+2t+e^{-2t}+8e^{-2t}=-1+2t+9e^{-2t}  

(this is the solution to the differential equation)

5 0
3 years ago
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