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AnnyKZ [126]
3 years ago
13

Please answer correctly! I will mark you as Brainliest!

Mathematics
1 answer:
spayn [35]3 years ago
8 0

Answer: V=\frac{1}{3}\pi r^{2}h

Step-by-step explanation:

This shape is a cone. Since we are looking for the shape's volume, we use it's volume formula.

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Can some please help with this? :)
den301095 [7]

Answer:

Step-by-step explanation:

The stuff that is yellow is the answer!

6 0
3 years ago
The point (1, −1) is on the terminal side of angle θ, in standard position. What are the values of sine, cosine, and tangent of
defon
The abscissa of the ordered pair, that is the x-coordinate, is equal to 1 and the ordinate, the y-coordinate, is equal to -1. In the cartesian plane, this point lies in the fourth (IV) quadrant. The standard position of the angle is that which has one of its side is in the x-axis.

Solve for the hypotenuse of the right triangle formed.
           h = sqrt((-1)² + (1)²) = √2
Below items show the calculation for each of the trigonometric functions.

 sin θ = opposite/hypotenuse = y/h = (-1)/(√2) = -√2/2
 cos  θ = adjacent/hypotenuse = x/h = (1)/√2 = √2/2
tan θ = opposite/adjacent = y/x = -1/1 = -1
7 0
3 years ago
Answer correct you get brainliest answer​
zloy xaker [14]

Answer:

y =  {x}^{2}  - 2

Or if you want with the value of h too.

y =  {(x - 0)}^{2}  - 2

Step-by-step explanation:

y = a {(x - h)}^{2}  + k

Find the value of h and k by using the formula.

h =  -  \frac{b}{2a}  \\ k =  \frac{4ac -  {b}^{2} }{4a}

From y = x²-2

a = 1 \\ b = 0 \\ c =  - 2

Substitute these values in the formula.

h =  -  \frac{0}{2(1)}  \\ h = 0

Therefore, h = 0.

k =  \frac{4(1)( - 2) -  {0}^{2} }{4(1)}  \\ k =  \frac{ - 8}{4}  \\ k =  - 2

Therefore, k = - 2.

From the vertex form, the vertex is at (h, k) = (0,-2). Substitute h = 0, a = 1 and k = -2 in the equation.

y = a {(x - h)}^{2}  + k \\ y = 1 {(x - 0)}^{2}  - 2 \\ y =  {(x)}^{2}  - 2 \\ y =  {x}^{2}  - 2

These type of equation where b = 0 can also be both standard and vertex form.

4 0
3 years ago
Solve the equation: <br><img src="https://tex.z-dn.net/?f=2%20%7Bx%7D%5E%7B2%7D%20%20%2B%207x%20-%203%20%3D%200" id="TexFormula1
Genrish500 [490]

Answer:

delta =  {7}^{2}   - 4 \times 2 \times ( - 3) \\  = 49 + 24 = 73 \\ x 1=  \frac{ - 7 +  \sqrt{73} }{4}  \\ x 2=  \frac{ - 7  -  \sqrt{73} }{4}

3 0
3 years ago
The points (4,7) and (r. – 5) lie on a line with slope – 3. Find the missing coordinate r ​
dusya [7]

Answer:

r=\frac{14}{3}

Step-by-step explanation:

Set up an equation and solve for r using the formula for slope:

\frac{5-7}{r-4}=-3\\ \\-2=-3(r-4)\\\\-2=-3r+12\\\\-14=-3r\\\\\frac{14}{3}=r

7 0
2 years ago
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