Answer:
42
Step-by-step explanation:
because the math
Answer: 200
Step-by-step explanation:
You see that from Monday to Tuesday they traveled 150 miles. By Wednesday it goes up 25. 150+25 = 175. By Thursday it goes up 25 more miles. 175+25=200.
Answer:
soit n un nombre entier quelconque; 2n sera pair et 2n+1 sera impair.
1) (2n)² = 4n² = 2 * 2n²
2) (2n+1)² = 4n² + 4n + 1 = 2*(2n² + 2n) + 1
3) 2n + 2m = 2*(n+m)
la somme de 2 nombres pairs est paire
(2n + 1) + (2m + 1) = 2n + 2m + 2 = 2 *(n + m + 1)
la somme de 2 nombres impairs est paire
Step-by-step explanation:
What you must do for this case is to rewrite the first expression to find its value.
We have then:
153 = 2 (z + z) n
Rewriting:
153 = 2n2z
Then,
2n (2z) -193
Substituting
153-193 = -40
Answer:
the value of 2n (2z) -193 is
-40
![\bf n^{th}\textit{ term of a geometric sequence}\\\\ a_n=a_1\cdot r^{n-1}\qquad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ r=\textit{common ratio}\\ ----------\\ a_1=4\\ r=3\\ a_n=324 \end{cases} \implies 324=4(3)^{n-1} \\\\\\ \cfrac{324}{4}=3^{n-1}\implies 81=3^{n-1}\implies 3^4=3^{n-1}\implies 4=n-1 \\\\\\ \boxed{5=n}\\\\](https://tex.z-dn.net/?f=%5Cbf%20n%5E%7Bth%7D%5Ctextit%7B%20term%20of%20a%20geometric%20sequence%7D%5C%5C%5C%5C%0Aa_n%3Da_1%5Ccdot%20r%5E%7Bn-1%7D%5Cqquad%20%0A%5Cbegin%7Bcases%7D%0An%3Dn%5E%7Bth%7D%5C%20term%5C%5C%0Aa_1%3D%5Ctextit%7Bfirst%20term%27s%20value%7D%5C%5C%0Ar%3D%5Ctextit%7Bcommon%20ratio%7D%5C%5C%0A----------%5C%5C%0Aa_1%3D4%5C%5C%0Ar%3D3%5C%5C%0Aa_n%3D324%0A%5Cend%7Bcases%7D%0A%5Cimplies%20%0A324%3D4%283%29%5E%7Bn-1%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Ccfrac%7B324%7D%7B4%7D%3D3%5E%7Bn-1%7D%5Cimplies%2081%3D3%5E%7Bn-1%7D%5Cimplies%203%5E4%3D3%5E%7Bn-1%7D%5Cimplies%204%3Dn-1%0A%5C%5C%5C%5C%5C%5C%0A%5Cboxed%7B5%3Dn%7D%5C%5C%5C%5C)
![\bf -------------------------------\\\\ \qquad \qquad \textit{sum of a finite geometric sequence}\\\\ S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ r=\textit{common ratio}\\ ----------\\ a_1=4\\ r=3\\ n=5 \end{cases} \\\\\\ S_5=4\left( \cfrac{1-3^5}{1-3} \right)\implies S_5=4\left(\cfrac{1-243}{-2} \right)](https://tex.z-dn.net/?f=%5Cbf%20-------------------------------%5C%5C%5C%5C%0A%5Cqquad%20%5Cqquad%20%5Ctextit%7Bsum%20of%20a%20finite%20geometric%20sequence%7D%5C%5C%5C%5C%0AS_n%3D%5Csum%5Climits_%7Bi%3D1%7D%5E%7Bn%7D%5C%20a_1%5Ccdot%20r%5E%7Bi-1%7D%5Cimplies%20S_n%3Da_1%5Cleft%28%20%5Ccfrac%7B1-r%5En%7D%7B1-r%7D%20%5Cright%29%5Cquad%20%0A%5Cbegin%7Bcases%7D%0An%3Dn%5E%7Bth%7D%5C%20term%5C%5C%0Aa_1%3D%5Ctextit%7Bfirst%20term%27s%20value%7D%5C%5C%0Ar%3D%5Ctextit%7Bcommon%20ratio%7D%5C%5C%0A----------%5C%5C%0Aa_1%3D4%5C%5C%0Ar%3D3%5C%5C%0An%3D5%0A%5Cend%7Bcases%7D%0A%5C%5C%5C%5C%5C%5C%0AS_5%3D4%5Cleft%28%20%5Ccfrac%7B1-3%5E5%7D%7B1-3%7D%20%5Cright%29%5Cimplies%20S_5%3D4%5Cleft%28%5Ccfrac%7B1-243%7D%7B-2%7D%20%20%5Cright%29)
and surely you know how much that is.