Answer:
$3,000 invested at 6%
$7,000 invested at 10%
Step-by-step explanation:
Maria had total $10,000 to invest.
Let x be the amount that Maria invested initially at 6% interest rate.
0.06x
Then she invested the remaining amount at 10% interest rate.
0.10(10,000 - x)
She received a total of $880 in interest.
0.06x + 0.10(10,000 - x) = 880
0.06x + 1000 - 0.10x = 880
-0.04x = 880 - 1000
-0.04x = -120
0.04x = 120
x = 120/0.04
x = $3,000
This is the amount that Maria invested initially at 6% interest rate.
The remaining amount is
10,000 - 3,000
$7,000
This is the remaining amount that she invested at 10% interest rate.
Because you are not adding the x's .When you add the coefficients, the variable comes along with it.
11, -8, and 7 are the answers...
Please mark as brainliest... I really need it...
To find the inverse, switch the variables and solve for f(x).
x = e^f(x) + 6
x - 6 = e^f(x)
f(x) = ln(x-6)
hope this helps :)
