The height of the ball 2 seconds after being thrown is 20.8m
In order to get the required quadratic function, we need to write the given information as coordinate.
- If the time the ball was initially thrown in the air, it was 7. 5 meters off the ground, this is written in a coordinate form as (0, 7.5)
- If after 1. 25 seconds, the ball was at its maximum height of 15.3125 meters in a coordinate form as (1.25, 15.3125)
Get the slope of the equation;
Get the y-intercept "b"
Recall that y = mx + b
Get the required equation:
Next is to get the height of the ball 2 seconds after being thrown
Hence the height of the ball 2 seconds after being thrown is 20.8m
Learn more on functions here: brainly.com/question/1214333
The question is asking you to find the axis of symmetry, which is the x-value of the vertex. In order to do that you need to factor the function to find the zeros and add the zeros together and divide by two to find the axis of symmetry.
y=-16x^2+608x
y=-16x(x-38)
Zeros: x=0 and x=38
38/2=19
Therefore it takes 19 seconds for the projectile to reach its maximum height.
Hope this helps!
What he said because. And so yea
Answer: f(6) = (6)2 + 1 = 36 + 1 = 37
If we wanted to find and expression for f(g(x)) we could plug in g(x), which is "x - 4" into the function f(x) wherever we see an "x". So:
f(x) = x2 + 1
f(g(x)) = (x - 4)2 + 1 because g(x) is "x - 4"
Step-by-step explanation:
You can always find a percent by setting up a fraction
and then doing the division.
To set up the fraction, the top number is some percent of the bottom number.
If 400 is some percent of 30, then the fraction is
400 / 30 .
Do the division: 400/30 = 13.333...
To turn a number into a percent, move
the decimal point two places that way ===> .
13.333... = 1,333.333 %
400 is (1,333 and 1/3) percent of 30 .
