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Marta_Voda [28]
3 years ago
11

Kalina is choosing a sandwich and a drink for lunch. She can choose between turkey, ham, and vegetarian sandwiches. She chooses

her drink from a selection of water, orange juice, milk, or lemonade. How many possible ways can one sandwich and one drink be chosen? If one more drink choice were added to the selection, the number of possible ways to choose one sandwich and one drink would increase by
Mathematics
2 answers:
Veronika [31]3 years ago
5 0
1.
3\cdot4=12

2.
3\cdot5=15

15-12=3
so, by 3
balandron [24]3 years ago
3 0

12 then 3

e2020

two different parts

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6th grade math i mark as brainliest
Natasha_Volkova [10]

Answer:

16

Step-by-step explanation:

8 0
4 years ago
What theorem states that if two sides and the included angle of one triangle are congruent to the corresponding parts of another
lianna [129]

The given statement is proved by side-angle-side (SAS) theorem.

Yes, if two sides and the included angle of one triangle are congruent to the corresponding parts of another triangle the triangles are congruent.

The statement is proved by SAS theorem

<u>Side-Angle-Side (SAS) theorem: </u>

The triangles are congruent if two sides and the included angle of one triangle are equivalent to two sides and the included angle of another triangle.

Hence, The given statement is proved by side-angle-side (SAS) theorem.

To read more about Angles

brainly.com/question/22472034

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7 0
1 year ago
How do you graph y=7/2x-2
RoseWind [281]
You can either make a table using any numbers you would like (I would suggest -5 to 5) and then graphing the rule

ex. (7/2)(-5)-2 = -19.5 (I multiplied (7/2) by -5 and then subtracted 2) 


Or you can put the rule in a graphing calculator and check the points from there 
8 0
3 years ago
I’m not quite sure what the answers are, I have tired this problem a variety of times and still get it wrong.
leva [86]

Check the picture below, keeping in mind that opposides sides and interior angles in a parallelogram are congruent.

5 0
2 years ago
Dos motos, A y B, toman la salida en una carrera de 90 km. La moto A realiza el recorrido con una velocidad media inferior en 20
aleksandr82 [10.1K]

Answer:

motorcycle A: 180 km/h

motorcycle B: 200 km/h

Step-by-step explanation:

To solve this question we need to write a system of equations for A and B, using the equation:

distance = speed * time

The speed of A is 20 less than the speed of B, so:

speedA = speedB - 20

And the time A traveled is 3 minutes (0.05 hours) more than B's time, so:

timeA = timeB + 0.05

Then, using the distance equation, we have that:

distanceB = speedB * timeB

90 = speedB * timeB

distanceA = speedA * timeA

90 = (speedB - 20) * (timeB + 0.05)

90 = speedB * timeB + 0.05 * speedB - 20*timeB - 1

90 = 90 + 0.05 * speedB - 20*timeB - 1

20*timeB = 0.05 * speedB - 1

timeB = (speedB - 20)/400

using this timeB in the distance equation, we have:

90 = speedB * (speedB - 20)/400

90 * 400 = speedB^2 - 20*speedB

speedB^2 - 20*speedB - 36000 = 0

Solving this quadratic equation, we have speedB = 200 km/h

And the speedA is:

speedA = speedB - 20 = 200 - 20 = 180 km/h

6 0
3 years ago
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