The answer is b because you take the average of the exam score and the course score, so it comes out to be about a 70
f(x) = 4x - x^2
1)
f(4) = 4(4) - 4^2 = 16 - 16 = 0
f(-4) = 4(-4) - (-4)^2 = -16 - 16 = -32
f(4) - f(-4) = 0 - (-32) = 32
2)
f(3/2) = 4(3/2) - (3/2)^2
f(3/2) = 6 - 9/4 = 15/4
√f(3/2) = √(15/4) = √15 / 2
3)
f(x + h) = 4(x + h) - (x + h)^2
= 4x + 4h -(x^2 + 2xh + h^2)
= 4x + 4h -x^2 - 2xh - h^2
f(x - h) = 4(x - h) - (x - h)^2
= 4x - 4h -(x^2 - 2xh + h^2)
= 4x - 4h -x^2 + 2xh - h^2
So
[f(x + h) -f(x - h) ] / 2h
= [4x + 4h -x^2 - 2xh - h^2 - ( 4x - 4h -x^2 + 2xh - h^2 )] / 2h
=( 4x + 4h -x^2 - 2xh - h^2 - 4x + 4h + x^2 - 2xh + h^2 ) / 2h
= (8h - 4xh) / 2h
= 2h(4 -2x) / 2h
= 4 - 2x
Answer: [f(x + h) -f(x - h) ] / 2h = 4 - 2x
Answer:
The value of the second expression is 14, so the expressions are equivalent.
Step-by-step explanation:
x=5
6+2(5)-2=
6+10-2=
16-2=
14
The other expression also came out to be 14, so they are equivalent.
It's pretty simple! So it looks like you are learning proportions. You would cross multiply to achieve your answer.
First, let's do your first problem:
2 12
--- = ----
5 n
You would take 5 and multiply it by 12 and get 60! Then you would do the same with 2 times n, giving you 2n (because you do not know what n represents YET.)
Now you should have this:
60=2n OR 2n=60
We must isolate our variable, in order to do that, get rid of two! But how? You would do this by dividing 2n by 2. Yet in equations, when you do something to one side, you must do it to the other because they must be EQUAL! (hence the "equa-" in equation)
2n=60
--- ---
2 2 DIVIDE 2 into 60
----------
n= 30 Simplify!
Your final answer for the first question is n= 30!
<h3><em>X CO-ORDINATE = 3</em></h3><h3><em>Y CO-ORDINATE = -7</em></h3><h3><em>HOPE IT HELPS.....BYE....</em></h3>
