From V= 4/3*pi*r^3
<span>dV/dt = 4pi(r^2)dr/dt </span>
<span>so when dV/dt=30 and r = 19 </span>
<span>30 = 4pi(361)dr/dt </span>
<span>dr/dt = 30/[4pi(361)] </span>
<span>now in </span>
<span>A = 4pir^2 </span>
<span>dA/dt = 8pi(r)dr/dt </span>
<span>= 8pi(19)*30/[4pi(361)] </span>
<span>= you finish it.</span>
<span>HOPE THIS HELPS.
</span>
Answer:
yes it is true
Step-by-step explanation:
if we take n=2 then
2°3-2=8-2=6
It doesn't change because to add fractions, you need a common denominator. To find it, they multiplied 1/3 by 2 to make 2/6, to add to the 3/6.
Try writing it in point-slope form and you will see why you have a problem.
slope m is equal to (y2-y1)/(x2-x1):
m = (y2-y1)/(x2-x1) = (2-6)/(-6 - -6) = -4/0
The denominator has a zero, so it is undefined.
Since the point-slope form requires "m" to be defined, you can't write the equation of the line using point-slope form.
Answer:
The vertical line test can be used to determine whether a graph represents a function. If we can draw any vertical line that intersects a graph more than once, then the graph does not define a function because a function has only one output value for each input value.
Step-by-step explanation:
The vertical line test can be used to determine whether a graph represents a function. If we can draw any vertical line that intersects a graph more than once, then the graph does not define a function because a function has only one output value for each input value.
I attached an Image you can visualize it clearly
P.S I ain't that good at drawing though :P
