Answer:
![\displaystyle y=\frac{3}{5}x-1](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y%3D%5Cfrac%7B3%7D%7B5%7Dx-1)
Step-by-step explanation:
<u>The Equation of a Line</u>
The equation of the line in slope-intercept form is:
![y=mx+b](https://tex.z-dn.net/?f=y%3Dmx%2Bb)
Where m is the slope and b the y-intercept.
The equation of a line passing through points (x1,y1) and (x2,y2) can be found as follows:
![\displaystyle y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y-y_1%3D%5Cfrac%7By_2-y_1%7D%7Bx_2-x_1%7D%28x-x_1%29)
We are given the points (5,2) and (0,-1), thus:
![\displaystyle y-2=\frac{-1-2}{0-5}(x-5)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y-2%3D%5Cfrac%7B-1-2%7D%7B0-5%7D%28x-5%29)
Operating:
![\displaystyle y-2=\frac{-3}{-5}(x-5)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y-2%3D%5Cfrac%7B-3%7D%7B-5%7D%28x-5%29)
![\displaystyle y-2=\frac{3}{5}(x-5)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y-2%3D%5Cfrac%7B3%7D%7B5%7D%28x-5%29)
To find the slope-intercept form, we continue to simplify the expression:
Removing the parentheses:
![\displaystyle y-2=\frac{3}{5}x-\frac{3}{5}\cdot 5](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y-2%3D%5Cfrac%7B3%7D%7B5%7Dx-%5Cfrac%7B3%7D%7B5%7D%5Ccdot%205)
![\displaystyle y-2=\frac{3}{5}x-3](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y-2%3D%5Cfrac%7B3%7D%7B5%7Dx-3)
Adding 2:
![\displaystyle y=\frac{3}{5}x-3+2](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y%3D%5Cfrac%7B3%7D%7B5%7Dx-3%2B2)
![\mathbf{\displaystyle y=\frac{3}{5}x-1}](https://tex.z-dn.net/?f=%5Cmathbf%7B%5Cdisplaystyle%20y%3D%5Cfrac%7B3%7D%7B5%7Dx-1%7D)
Answer:I don’t understand srry it kinda confusing
Step-by-step explanation:
Answer:
-2/3
Step-by-step explanation:
multiply each side by u +1 to get it out of the denominator
-3(u + 1) = -1
now use distributive property
-3u - 3 = -1
add the 3 to move it over
-3u = 2
now divide by -3
u = -2/3
Answer:
0.999987
Step-by-step explanation:
Given that
The user is a legitimate one = E₁
The user is a fraudulent one = E₂
The same user originates calls from two metropolitan areas = A
Use Bay's Theorem to solve the problem
P(E₁) = 0.0131% = 0.000131
P(E₂) = 1 - P(E₁) = 0.999869
P(A/E₁) = 3% = 0.03
P(A/E₂) = 30% = 0.3
Given a randomly chosen user originates calls from two or more metropolitan, The probability that the user is fraudulent user is :
![P(E_2/A)=\frac{P(E_2)\times P(A/E_2)}{P(E_1)\times P(A/E_1)+P(E_2)\times P(A/E_2)}](https://tex.z-dn.net/?f=P%28E_2%2FA%29%3D%5Cfrac%7BP%28E_2%29%5Ctimes%20P%28A%2FE_2%29%7D%7BP%28E_1%29%5Ctimes%20P%28A%2FE_1%29%2BP%28E_2%29%5Ctimes%20P%28A%2FE_2%29%7D)
![=\frac{(0.999869)(0.3)}{(0.000131)(0.03)+(0.999869)(0.3)}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B%280.999869%29%280.3%29%7D%7B%280.000131%29%280.03%29%2B%280.999869%29%280.3%29%7D)
![\frac{0.2999607}{0.00000393+0.2999607}](https://tex.z-dn.net/?f=%5Cfrac%7B0.2999607%7D%7B0.00000393%2B0.2999607%7D)
![\frac{0.2999607}{0.29996463}](https://tex.z-dn.net/?f=%5Cfrac%7B0.2999607%7D%7B0.29996463%7D)
= 0.999986898 ≈ 0.999987
Answer:
Your answer is B.
Step-by-step explanation:
Since the origin is 0, start at 0.
Next, since the x coordinate is always first, we would move left 3, as the numbers on the left are negative.
Next, we would move up 7 from that point, and that is where the point (-3, 7) is located on a coordinate grid.
I hope this helps! :)