Answer:
Step-by-step explanation:
The gradient = change in y / change in x
When the x value increases by 1, the y value decreases by 2 so -2 / 1 = -2
The y intercept is 4, so it is +4
Answer:
Part c: Contained within the explanation
Part b: gcd(1200,560)=80
Part a: q=-6 r=1
Step-by-step explanation:
I will start with c and work my way up:
Part c:
Proof:
We want to shoe that bL=a+c for some integer L given:
bM=a for some integer M and bK=c for some integer K.
If a=bM and c=bK,
then a+c=bM+bK.
a+c=bM+bK
a+c=b(M+K) by factoring using distributive property
Now we have what we wanted to prove since integers are closed under addition. M+K is an integer since M and K are integers.
So L=M+K in bL=a+c.
We have shown b|(a+c) given b|a and b|c.
//
Part b:
We are going to use Euclidean's Algorithm.
Start with bigger number and see how much smaller number goes into it:
1200=2(560)+80
560=80(7)
This implies the remainder before the remainder is 0 is the greatest common factor of 1200 and 560. So the greatest common factor of 1200 and 560 is 80.
Part a:
Find q and r such that:
-65=q(11)+r
We want to find q and r such that they satisfy the division algorithm.
r is suppose to be a positive integer less than 11.
So q=-6 gives:
-65=(-6)(11)+r
-65=-66+r
So r=1 since r=-65+66.
So q=-6 while r=1.
Answer:
Wibur cannot rescind the contract based on his unilateral mistake.
Step-by-step explanation:
Consider the provided information.
Wilbur types $40 instead of $400 in the reserve price box.
Wilbur does not notice his mistake until after the auction is over and someone has purchased his stamp collection for $75.
This scenario fall into unilateral mistake.
Unilateral error arises when the subject matter or the terms found in the contract agreement are misunderstood by only one party.
Here it is Wibur's fault that he types $40 instead of $400.
This is not a mutual mistake.
Therefore he cannot rescind the contract.
Wibur cannot rescind the contract based on his unilateral mistake.
Answer:
Approximately Normal, with a mean of 950 and a standard error of 158.11
Step-by-step explanation:
To solve this question, we need to understand the Central Limit Theorem.
The Central Limit Theorem estabilishes that, for a random variable X, with mean 
and standard deviation 
, a large sample size can be approximated to a normal distribution with mean and standard deviation, which is also called standard error 
.
In this problem, we have that:
The sampling distribution of the sample mean amount of money in a savings account is
By the Central Limit Theorem, approximately normal with mean 
and standard error 
So the correct answer is:
Approximately Normal, with a mean of 950 and a standard error of 158.11
It's 35 because 10 plus 5 is 15. You the subtract it by 50 and you get 35.
