Question:
A solar lease customer built up an excess of 6,500 kilowatts hour (kwh) during the summer using his solar panels. when he turned his electric heat on, the excess be used up at 50 kilowatts hours per day
.
(a) If E represents the excess left and d represent the number of days. Write an equation for E in terms of d
(b) How much of excess will be left after one month (1 month = 30 days)
Answer:
a. 
b. 
Step-by-step explanation:
Given
Excess = 6500kwh
Rate = 50kwh/day
Solving (a): E in terms of d
The Excess left (E) in d days is calculated using:

The expression uses minus because there's a reduction in the excess kwh on a daily basis.
Substitute values for Excess, Rate and days


Solving (b); The value of E when d = 30.
Substitute 30 for d in 



<em>Hence, there are 5000kwh left after 30 days</em>
Answer:
0
Step-by-step explanation:
The five smallest prime numbers are 2, 3, 5, 7 and 11.
2 × 3 × 5 × 7 × 11
= 2310
Divide by 42.
2310/42
= 55, Remainder 0
Answer:
its 4 and my brain is about to blow up cause i just know this
Step-by-step explanation:
(x,y)
sub points to see if we get true statemtn
(2,12)
x=2 and y=12
12-5=5(2)
7=10
false
no, (2,12) is not a point
(-2,-5)
x=-2
y=-5
-5-5=5(-2)
-10=-10
true
(-2,-5) is a soltuion
(-2,-5) is the only solution given that works
Answer:
[1] = 6
x = -3/2 is the root
Step-by-step explanation:
A perfect square trinomial is of the form ...
(a + b)² = a² +2ab +b²
You have ...
- a²=16w² ⇒ a = 4w
- b² = 36 ⇒ b = 6
- 2ab = 2(4w)(6) = 48w
Then the factorization is ...
16w² +48w +36 = (4w +6)²
This will be zero when x = -6/4 = -3/2.