3 years ago

What is the remainder when the product of the 5 smallest prime numbers is divided by 42?

Mathematics

1 answer:

sveta [45]3 years ago

5 0

Answer:

Step-by-step explanation:

The five smallest prime numbers are 2, 3, 5, 7 and 11.

2 × 3 × 5 × 7 × 11

= 2310

Divide by 42.

2310/42

= 55, Remainder 0

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