Would it be 4(1)^2+2(2(1)+2)^2=100
Answer:
20= v+9+( -16 )
20= v-( 7 )
27= v
Step-by-step explanation:
Adding a negative is the sane as subtracting. Add like terms. Add 7 to both sides. 27= v
You can set up an system of equations
x=2y+8
x-y=25
Substitute x in to the second equation
2y+8-y=25
y+8=25
y=17
Substitute the y back in to the first equation.
x=2(17)+8=42
Answer:
r = 20
Step-by-step explanation:
-4 = r/20 - 5
-4 + 5 = r/20 - 5 + 5
1 = r/20
1 * 20 = r/20 * 20
r = 20
Answer:
The maximum height of the ball is 256m
Step-by-step explanation:
Given the equation of a pathway modelled as pathway can be modeled by h = -16t² + 128t
At maximum height, the velocity of the ball is zero.
velocity = dh/dt
velocity = -32t + 128
Since v = 0 at maximum height
0 = -32t+128
32t = 128
t = 128/32
t = 4seconds
The maximum height can be gotten by substituting t = 4 into the modelled equation.
h = -16t² + 128t
h = -16(4)²+128(4)
h = -16(16)+512
h = -256+512
h = 256m
