According to the temperature changes, it is found that:
- On Tuesday, the temperature at Noon was of -28.5 ºF.
- On Wednesday, the temperature at Midnight was of -5.5 ºF.
- On Thursday, the change was of -11.8 ºF.
- On Friday, the temperature at Noon was of -4.5 ºF.
<h3>What is the temperature change?</h3>
- The temperature change during a period is given by the <u>temperature at the end of the period subtracted by the temperature at the start of the period</u>.
On Tuesday:
- At the start of the period, the temperature was of -17.5 ºF.
- The change was of -11 ºF.
Hence:



On Tuesday, the temperature at Noon was of -28.5 ºF.
On Wednesday:
- At the end of the period, the temperature was of 10 ºF.
- The change was of 15.5 ºF.
Hence:


On Wednesday, the temperature at Midnight was of -5.5 ºF.
On Thursday:
- At the end of the period, the temperature was of -24 ºF.
- At the start of the period, the temperature was of -12.2 ºF.
Hence:

On Thursday, the change was of -11.8 ºF.
On Friday:
- At the start of the period, the temperature was of -21.8 ºF.
- The change was of 17.3 ºF.
Hence:



On Friday, the temperature at Noon was of -4.5 ºF.
You can learn more about change at brainly.com/question/24313700
Answer
Step-by-step explanation:
Law of sines: SinB/15 = SinA/BC
B = 90
A = 180-90-21=69°
BC= (15*SinA)/SinB = (15*sin69)/1 ≈ 14m
Answer:
We should reject H0
At the 5% significance level, there is sufficient evidence to conclude that the die is not fair.
Step-by-step explanation:
Null hypothesis is a statement that is to be tested against the alternative hypothesis and then decision is taken whether to accept or reject the null hypothesis. The critical value is 15.091 and test statistic is 11.070. The null hypothesis is rejected or accepted on the basis of level of significance. When the p-value Test statistics is greater than level of significance we fail to reject the null hypothesis and null hypothesis is then accepted. In the given case p-value is less than critical value then we should reject the null hypothesis.