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3 years ago

Perform the indicated operation.

Mathematics

2 answers:

LenKa [72]3 years ago

8 0

This should be your answer i hope this helps

makkiz [27]3 years ago

4 0

Answer:

X²/Z²

Step-by-step explanation:

((Xy+xz)/(xz-z²) )*((xy-yz)/(xz+yz))/((y²+yz)/(x²+xy))

= ((Xy+xz)/(xz-z²) )*(y/z(x-z)/(x+y) * x/y(x+y)/(y+z)

= ((Xy+xz)/(xz-z²) )*(x/z(x-z)/(y+z))

= (X/z(y+z)/(x-z)) * (x/z(x-z)/(y+z))

= X²/Z²

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Leni [432]

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3 years ago

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PLEASE ANSWER ASAP FOR BRANLEST!!!!!!!!!!!!!!!<br> Solve the equation<br> b/4 +2 = -1<br> what is b?

BARSIC [14]

The answer is b=-12

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3 years ago

A parabola opening up or down has vertex (0,0) and passes through (12, -18). Write its

denis-greek [22]

The equation is y= -1/8x^2

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3 years ago

What is the answer to this?

Keith_Richards [23]

Answer:

Y = 28.31

Z = 13.29

Angle A = 28

Step-by-step explanation:

For Angle A:

Remember a triangle has a total of 180 degree angles. So set up your formula as

180 - 62 -90 = Angle A

For Y:

The sine of an angle is equal to the ratio of the opposite side to the hypotenuse.

sin (B) = opp/hyp or b/c or (y)

sinB = 62

b = 25

Rewrite as c=b/2SinB -> c=25/sin62 -> Y = 28.31

For Z:

Use the Pythagorean theorem to find the unknown side.

$z^{2} = 28.31^{2} - 25^{2}$

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3 0

3 years ago

Find the solution set of the following quadratic equations using the quadratic formula.

oksian1 [2.3K]

Answer:

<h3> 1) $x_1=\dfrac{7+\sqrt{13}}2\,,\quad x_2=\dfrac{7-\sqrt{13}}2$ </h3><h3> 2) $x_1=-\dfrac13\,,\quad x_2=-3$ </h3>

Step-by-step explanation:

$x^2 - 7x + 9 = 0\quad\implies\quad a=1\,,\ b = -7\,,\ c=9\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-(-7)\pm\sqrt{(-7)^2-4\cdot1\cdot9}}{2\cdot1}=\dfrac{7\pm\sqrt{49-36}}2\\\\x_1=\dfrac{7+\sqrt{13}}2\,,\quad x_2=\dfrac{7-\sqrt{13}}2$

<h3>2)</h3><h3> $3x^2 + 10x=-3\\\\3x^2+10x+3=0\quad\implies\quad a=3\,,\ b =10\,,\ c=3\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-10\pm\sqrt{10^2-4\cdot3\cdot3}}{2\cdot3}= \dfrac{-10\pm\sqrt{100-36}}6\\\\x_1=\dfrac{-10+\sqrt{64}}6=\dfrac{-10+8}6=-\dfrac13\,,\qquad x_2=\dfrac{-10-8}6=-3$ </h3>

7 0

3 years ago