Answer:
the first one
Step-by-step explanation:
let "a number" = x
a number is divided by 3 => x/3
14 is added to the quotient => (x/3) + 14
The result is 33 => " = 33"
Solve for x
(x/3) + 14 = 33
Isolate the x. Note the equal sign. What you do to one side you do the other.
Subtract 14 from both sides
(x/3) + 14 (-14) = 33 (-14)
x/3 = 19
Isolate the x. Multiply 3 to both sides
x/3(3) = 19(3)
x = 19(3)
x = 57
57 is your original number
hope this helps
Answer:
3
Step-by-step explanation:
note that zeros and x-intercepts are the same with different names
There are 2 zeros from the quadratic factor and 1 from the linear factor.
To find them equate the function to zero, that is
(x² - x - 2)(3x - 2) = 0
(x - 2)(x + 1)(3x-2) = 0 ← factoring the quadratic
equate each factor to zero and solve for x
x - 2 = 0 ⇒ x = 2
x + 1 = 0 ⇒ x = - 1
3x - 2 = 0 ⇒ x = 
The statement is false because when you use distributive property, you get -12=-4+16 and when you add 16 to -4, you'll get 12, not -12, making the statement false.
The division is using extra zeros.
2 * 16 = 32, but 3200 was placed below 3426.
Now 1 * 16 = 16, so 160 goes below 226.
The number that goes in the box is 160.
