Here you go look at the drawings
Answer:
depending on the form of how your question is actually written .. The answer will either be :
x= -1
or
There are no values of x that make the equation true. No solution.
Step-by-step explanation:
Hope this helps
This is a linear differential equation of first order. Solve this by integrating the coefficient of the y term and then raising e to the integrated coefficient to find the integrating factor, i.e. the integrating factor for this problem is e^(6x).
<span>Multiplying both sides of the equation by the integrating factor: </span>
<span>(y')e^(6x) + 6ye^(6x) = e^(12x) </span>
<span>The left side is the derivative of ye^(6x), hence </span>
<span>d/dx[ye^(6x)] = e^(12x) </span>
<span>Integrating </span>
<span>ye^(6x) = (1/12)e^(12x) + c where c is a constant </span>
<span>y = (1/12)e^(6x) + ce^(-6x) </span>
<span>Use the initial condition y(0)=-8 to find c: </span>
<span>-8 = (1/12) + c </span>
<span>c=-97/12 </span>
<span>Hence </span>
<span>y = (1/12)e^(6x) - (97/12)e^(-6x)</span>
Answer:
17 + 2i
Step-by-step explanation:
Given
(2 - 3i) + 5i(1 - 3i) ← distribute both parenthesis
= 2 - 3i + 5i - 15i² [ i² = - 1 ]
= 2 + 2i + 15
= 17 + 2i ← in standard form
no it is not an intercept form because the y has to be by itself.
it should be in the form of y=mx+b
