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evablogger [386]
3 years ago
12

PLSSSSSSSSSS HELP!!!! Which element would be considered a great insulator ?

Chemistry
2 answers:
marta [7]3 years ago
8 0
The greatest insulator is D) Sulfur
Charra [1.4K]3 years ago
7 0

Answer:

C.Sulfur

Explanation:

Insulators: A material that heat does not move through easily

Sulfur's electrons are very tightly held and cannot move around, therefore it is more of an insulator.

You might be interested in
Determine the total pressure of all gases (at STP) formed when 50.0 mL of TNT (C3H5(NO3)3, , molar mass = 227.10 g/mol) reacts a
bija089 [108]

Answer:

Total pressure is 1189 atm

Explanation:

This is the reaction:

4C₃H₅(NO₃)₃  →  6N₂  +  O₂  +  12CO₂  +  10H₂O

As we have the volume of TNT, we must know the density to find out the mass and then, apply molar mass to calculate mole.

TNT density = 1.654 g/mL

Density = mass / volume

1.654 g/mL = TNT mass / 50mL

1.654 g/mL . 50mL = TNT mass → 82.7 g

Mass / Molar mass = Mol → 82.7 g / 227.1 g/m = 0.364 mole

Now, we can calculate all the mole for the formed gases.

4 mole of TNT produce 6 mole N₂ ___ 1 mol O₂ __ 12 mole dioxide __ 10 mole of water

0.364 mole of TNT will produce:

- (0.364  . 6) /4 = 0.546 mole of produced nitrogen

- (0.364 . 1) /4 =  0.091 mole of produced oxygen

- (0.364 . 12) /4 = 1.092 mole of produced dioxide

- (0.364 . 10) /4 = 0.91 mole of produced vapour of water.

Total mole = 0.564 + 0.091 + 1.092 + 0.91 = 2.657 mole

Let's apply the Ideal Gases Law to find the total pressure, at STP

In STP, pressure is 1 atm for 1 mole at 273K, in a volume of 22.4 mL

But we have a volume of 50mL, and we have 2.657 total mole

Don't forget to convert 50 mL to L, cause the units for R

50 mL = 0.050L

P . 0.050L = 2.657 mol . 0.082L.atm/mol.K . 273K

P = (2.657 mol . 0.082L.atm/mol.K . 273K) / 0.050L

P = 1189 atm

3 0
3 years ago
which element has the electron configuration of 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6 6s2 4f14 5d10 6p6 7s2 5f14 6d8
salantis [7]

Answer:

Darmstadtium

Explanation:

An element with the electronic configuration 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p⁶6s²4f¹⁴5d¹⁰6p⁶7s²5f¹⁴6d⁸ has 110 electrons in its electron shells.

Since the element is a neutral atom, this number is also equal to its atomic number. Therefore, its atomic number is 110.

The element in the period table that has an atomic number of 110 is Darmstadtium, a d-block element, thus a transittion metal. It also belong to period 7 in the Periodic table of elements.

3 0
3 years ago
Help Please! Will give brainlyest for correct answers! 99 points!!
lapo4ka [179]

Answer:

1- 1.54 mol.

2- 271.9 kPa.

3- Yes, the tires will burst.

4- 235.67 kPa.

5- As, the temperature increased, the no. of molecules that has minimum kinetic energy increases as shown in image 1 that represents the Maxwell’s Distribution of Speeds of molecules. "Kindly, see the explanation and the attached images".

Explanation:

<u><em>Q1- How many moles of nitrogen gas are in each tire?  </em></u>

  • To calculate the no. of moles of nitrogen gas in each tire, we can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the nitrogen gas (P = 247.0 kPa/101.325 = 2.44 atm),

V is the volume of the nitrogen gas (V = 15.2 L),

n is the no. of moles of the nitrogen gas (n = ??? mole),

R is the general gas constant (R = 0.082 L.atm/mol.K),

T is the temperature of the nitrogen gas (T = 21°C + 273 = 294 K).

∴ n = PV/RT = (2.44 atm)(15.2 L)/(0.082 L/atm/mol.K)(294.0 K) = 1.54 mol.

<u><em>Q2: What would the maximum tire pressure be at 50 degrees C?  </em></u>

  • Now, the temperature is raised to be 50°C (T = 50°C + 273 = 323 K).
  • The pressure can be calculated using the general gas law: PV = nRT.

∴ P = nRT/V = (1.54 atm)(0.082 L/atm/mol.K)(323.0 K)/(15.2 L) = 2.68 atm = 271.9 kPa.

<em>Q3: Will the tires burst in Spokane? Explain.</em>

  • <em>Yes, the tires will burst because the internal pressure be 271.9 kPa that exceeds 270 kPa, the pressure above which the tires will burst. </em>

<u><em>Q4: If you must let nitrogen gas out of the tire before you go, to what pressure must you reduce the tires before you start your trip? (Assume no significant change in tire volume.)  </em></u>

  • To get the pressure that we must begin with:

Firstly, we should calculate the no. of moles at:

T = 55°C + 273 = 328 K,

Pressure = 270 kPa (the pressure above which the tires will burst). (P =270 kPa/101.325 = 2.66 atm).

V = 15.2 L, as there is no significant change in tire volume.

∴ n = PV/RT = (2.66 atm)(15.2 L)/(0.082 L.atm/mol.K)(328 K) = 1.5 mol.

  • <em>1.5562 moles of N₂ in the tires will give a pressure of 270 kPa at 55°C, so this is the minimum moles of N₂ that will make the tires burst. </em>
  • <em>Now, we can enter this number of moles into the original starting conditions to tell us what pressure the tires will be at if we start with this number of moles of N₂. </em>

P = ???  

V = 15.6 L.

n = 1.5 mol

T = 21°C + 273 = 294.0 K  

R = 0.0821 L.atm/mol.K.

∴ P = nRT/V = (1.5 mol x 0.082 x 294.0 K) / (15.6 L) = 2.2325 atm = 235.67 kPa.

So, the starting pressure needs to be 235.67 kPa or just under in order for the tires not to burst.

<u><em>Q5: Create a drawing of the tire and show a molecular view of the air molecules in the tire at 247 kpa vs the molecular view of the air molecules after the tires have been heated. Be mindful of the number of molecules that you use in your drawing in the before and after scenarios. Use a caption to describe the average kinetic energy of the molecules in both scenarios.</em></u>

<u><em /></u>

  • <em>As, the temperature increased, the no. of molecules that has minimum kinetic energy increases as shown in “image 1” that represents the Maxwell’s Distribution of Speeds of molecules. </em>
  • <em>The no. of molecules that possess a critical K.E. of molecules increases due to increasing the temperature activate the motion of molecules with high velocity as </em>
  • <em>(K.E. = 3RT/2), K.E. directly proportional to the temperature of the molecules (see image 2). </em>
  • <em>Also, the average speed of molecules increases as the K.E of the molecules increases (see image 3). </em>

5 0
3 years ago
Four gases are described below.
Gnom [1K]

Answer:

d

Explanation:

8 0
3 years ago
Which two factors must be considered when predicting whether two substances will dissolve in each other?
r-ruslan [8.4K]

The two factors must be considered when predicting whether two substances will dissolve in each other are type of bonds and size of the molecules are two factors.

<h3>What is solubility?</h3>

Solubility is the ability of solute particles to dissolve in any solvent, and solubility is directly proportional to the dissolving ability of the solute.

Solubility of any substance depends on the type of the bond present in the solute molecule i.e. polar or non polar. And it is also depends on the size of the solute as size defines the surface tenssion of the substance.

  • Number of bonds and shape of molecules are also define the solubility but not at that extent as their type and shape.

Hence type of bonds and size of the molecules are two factors.

To know more about dissolution, visit the below link:
brainly.com/question/26073928

6 0
2 years ago
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