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Gemiola [76]
3 years ago
13

Using these metal ion/metal standard reduction potentials calculate cell potential for Cu2+(aq) + Cd(s) →Cd2+(aq)+ Cu(s) Cu2+(aq

)|Cu(s) + 0.34 VNi2+(aq)|Ni(s) -0.25 Cd2+(aq)/Cd(s) -0.4V
Chemistry
1 answer:
Katena32 [7]3 years ago
4 0

Solution :

Cd(s) ---------------------->  Cd^{+2} (aq) + 2e^-      ,     E_0  =   0.34 v

Cu^{+2}  (aq)  +   2e^-  ------------> Cu (s)             ,     E_0  =  -0.04 v

----------------------------------------------------------------------------------------------

Cd(s)  +  Cu^{+2}  (aq)  ------------->  Cd^{+2} (aq)  +  Cu (s)   ,      E_0  =  0.30 v  

The cell potential is defined as the measure of \text{ potential difference }  between the \text{two half cells} of an electrochemical cell.  

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