1 mm
Km etc
Hm etc
Dam etc
M 0.001
Dm 0.01
Cm 0.1
MM 1
Answer:
80%
Step-by-step explanation:
So 2 is 2 and 1 3 and 5 are odd so it is 4/5 and as a percent it is 80%
The feasible region is the region that comes from intersecting the different regions described by the equations that constrain the problem.
Let's take a look:
From this, we can conclude that the vertices of the feasible region are:
Since x=2, you plug it into your equation by replacing all the x with 2. You would then solve it by following the PEMDAS rule.
y= 4(2) + 2(2)^2 - (2)^3
y= 4(2) +2(4) - 8
y= 8 + 8 - 8
y= 16 - 8
y= 8