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3 years ago

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A store sells boxes of juice in equal size packs.Garth bought 36 boxes, Rico bought 18 boxes and Mai bought 45 boxes.what is the

greatest number of boxes in each pack.how many packs did each person buy if each box contained the greatest number of boxes possible

1 answer:

Scorpion4ik [409]3 years ago

7 0

This is just a case of GCF (Greatest common factor). And if you take a quick look at these numbers, you can see that the GCF is 9. So your answer is 9.

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Inverse Function In Exercise,analytically show that the functions are inverse functions.Then use the graphing utility to show th

DanielleElmas [232]

Answer:

$g^{-1}(x)=f(x)=e^{\frac{x}{3}}$

Step-by-step explanation:

We have been given two functions as $g(x)=\text{ln}(x^3)$ and $f(x)=e^{\frac{x}{3}}$ . We are asked to show that both functions are inverse of each other algebraically and graphically.

Let us find inverse function of $g(x)=\text{ln}(x^3)$ as:

$y=\text{ln}(x^3)$

Interchange x and y values:

$x=\text{ln}(y^3)$

Using log property $\text{ln}(a^b)=b\cdot \text{ln}(a)$ , we will get:

$x=3\cdot \text{ln}(y)$

$\frac{x}{3}=\frac{3\cdot \text{ln}(y)}{3}$

$\frac{x}{3}=\text{ln}(y)$

Using log definition; If $\text{log}_a(b)=c$ , then $b=a^c$ , we will get:

$y=e^{\frac{x}{3}}$

$g^{-1}(x)=e^{\frac{x}{3}}$

Therefore, we can see that function $f(x)=e^{\frac{x}{3}}$ is inverse of function $g(x)=\text{ln}(x^3)$ .

We can see that both functions are symmetric about line $y=x$ , therefore, both functions are inverse of each other.

8 0

4 years ago

Can anyone explain how to do this? The answer isn't as important as the explanation. My teacher gave us a video w/o an example l

solong [7]

Answer:

x = 182.53

Step-by-step explanation:

Use trigonometric ratios to find the whole side length (a) adjacent to 20° and the side length (b) adjacent to 57° respectively. Then find the difference. That would give you the value of x. That is: a - b = x

Let's solve.

✍️Finding the whole side length adjacent to 20°:

Opp = 87

Adjacent length = ? = a

$\theta = 20$

Thus,

$tan(\theta) = \frac{opposite}{adjacent}$

Plug in the values

$tan(20) = \frac{87}{a}$

Multiply both sides by a

$tan(20) \times a = \frac{87}{a} \times a$

$tan(20) \times a = 87$

Divide both sides by tan(20)

$\frac{tan(20) \times a}{tan(20)} = \frac{87}{tan(20)}$

$a = \frac{87}{tan(20)}$

$a = 239.03$

Finding the side length adjacent to 57°:

Opp = 87

Adjacent length = ? = b

$\theta = 57$

Thus,

$tan(\theta) = \frac{opposite}{adjacent}$

Plug in the values

$tan(57) = \frac{87}{b}$

Multiply both sides by b

$tan(57) \times b = \frac{87}{b} \times b$

$tan(57) \times b = 87$

Divide both sides by tan(57)

$\frac{tan(57) \times b}{tan(57)} = \frac{87}{tan(57)}$

$b = \frac{87}{tan(57)}$

$b = 56.50$

Therefore:

x = a - b

x = 239.03 - 56.50

x = 182.53

4 0

3 years ago

A shipment of 20 DVDs has arrived at a video rental store. Based on past experience, the manager knows that 10% of all new DVDs

aleksley [76]

Answer:

The probability is 0.081

Step-by-step explanation:

Here, we want to calculate the probability that the 3rd inspection will be defective.

What this means is that the first two would

not be defective.

Probability of having a defective DVD = 10% = 10/100 = 0.1

Probability of not having a defective DVD = 1 -0.1 = 0.9

So the probability of third being defective = Probability of first not defective * Probability of second not defective * Probability of third defective

= 0.9 * 0.9 * 0.1 = 0.081

7 0

3 years ago

George Orwell was visiting London and left his hotel at 8:00 am and returned at 9:00 pm. That day, he was recorded 286 times by

cupoosta [38]

Orwell, on average, was photographed 22 times every hour.

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3 years ago

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How much time did he have between the end of the test and beginning of football practice

bagirrra123 [75]

He had 26 minutes. He finished the test at 3:49.

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4 years ago

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