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stira [4]
3 years ago
10

at a football game 95% of people attending were supporting the home team while 5% were supporting the visiting team. if the tota

l number of people attending the game was 4000 how many people attending were supporters of the home team ?
Mathematics
1 answer:
Paraphin [41]3 years ago
5 0

Answer:

3800

Step-by-step explanation:

The first step you want to do is make a proportion

x/4000=95/100

Next you are going to cross multiply which his 4000 times 95 equals 380000 and then multiply 100 times x which is 100x.

Then you are going to divide both sides by 100 and you will cross out the x from the 100 and get only x and then divide 380000 divided by 100 and 3800

Which leaves you with x=3800

3800 people were attending to support the home team

Hope this helps :)

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Answer:

Differential equation

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Solution

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Value of constant k=0.327 days^(-1)

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Step-by-step explanation:

We know

y(t): proportion of people that heard the rumor

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Differential equation

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y(0)=0.2\\y(3)=0.4\\\\y(0)=0.2=\frac{1}{1-Ce^0}\\\\1-C=1/0.2\\\\C=1-1/0.2= -4\\\\\\y(3)=0.4=\frac{1}{1+4e^{-3k}} \\\\1+4e^{-3k}=1/0.4\\\\e^{-3k}=(2.5-1)/4=0.375\\\\k=ln(0.375)/(-3)=0.327\\\\\\y=\frac{1}{1+4e^{-0.327t}}

Value of constant k=0.327 days^(-1)

At what time the rumor reaches 80%?

y(t)=0.8=\frac{1}{1+4e^{-0.327t}} \\\\1+4e^{-0.327t}=1/0.8=1.25\\\\e^{-0.327t}=(1.25-1)/4=0.0625\\\\t=ln(0.0625)/(-0.327)=8.48

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