Hey there!
To start, the slope intercept equation format is y=mx+b where m=the slope and b=the y-intercept.
Because you appear to have a coordinate set to plug in for x and y as well as a slope of 4, you can plug your known values into the slope intercept equation:
y=mx+b
coordinate: (1,6)
y=6 (the y value of the coordinate point)
x=1 (the x value of the coordinate point)
m=4 (the slope of the equation, given)
6=4(1)+b
Because b, your y-intercept is your only missing value, you can simplify your equation and solve for b:
6=4(1)+b
6=4+b
b=2
Now that you have your two needed values, your slope and your y-intercept, your final equation should be y=4x+2, or the third choice.
Hope this helps and I hope you have a wonderful rest of your day! :)
<h2>
Greetings!</h2>
Answer:
1:60
Step-by-step explanation:
Because no ratios have been included, I will just find the simplified version. To simplify a number you need to find the highest number that goes into both numbers. In this case it is 5.
Now, divide both sides by 5:

Or:
60 : 1
So the ratio of raisins to boxes is 60:1, or 1:60 for boxes to raisins.
<h2>Hope this helps!</h2>
Answer:
Step-by-step explanation:
(9*20)-(8*6) = 132 sq cm
Answer: $18
Step-by-step explanation:
Let x= Pretax price of the meal.
Given: Sales tax = 8%
Tip percent = 20%
As per given ,
Amount spent = ( Pretax price) + (Sales tax ) of (Pretax price) + (Tip percent)of (Pretax price)
= x+ 8% of x + 20% of x
= x +0.08+0.20x
= 1.28x
∵ Amount spent = $23.04
So,

Hence, the pretax price of the meal= $18.
Consider a system of inequalities
Consider inequality in two variable
1. a x + b y ≤ c
2 . p x + q y ≥ r 3. x ≥ 0 4. y≥ 0
By drawing the graph ,You can find the region bounded by inequality 1, then reason bounded by inequality 2 , and then you can find the region common to both the inequality.
Consider the given inequality
x + y ≤2
x + y ≥1,
x≥ 0, y≥0.
You can find the solution below.
So, the Statement, To solve a system of inequalities graphically, you just need to graph each inequality and see which points are in the overlap of the graphs is True.