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Irina18 [472]
3 years ago
8

What percent of 21 is 28?

Mathematics
2 answers:
Juli2301 [7.4K]3 years ago
7 0

Answer:

75%

Step-by-step explanation:

Sorry it took so long for me to see this

100%/x%=28/21

(100/x)*x=(28/21)*x       - we multiply both sides of the equation by x

100=1.333*x       - we divide both sides of the equation by (1.333) to get x

100/1.333=x

75=x

x=75

21 is 75% of 28

Good luck have a Nice Day

laiz [17]3 years ago
6 0

Answer:75

Step-by-step explanation:

21 divded by 28 times 100= 75

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How do you convert rates? Example: 8gal/h=? Or/min
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The ration of minutes to hours is 60/1

Therefore, 8gal/60min = (2/15)gal/min
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3 years ago
Write the equation of the circle with center (3, 2) and (−6, −4) a point on the circle.
yulyashka [42]
The equation for a circle is as followed:

(x-h)^2+(y-k)^2=r^2

where the center of the circle is at (h,k) and the radius of the circle is r.

We are given (h,k) and need to find the radius. To do so, we can use the distance formula to find the distance from the  center to the point on the circle:

d= \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}

Plug in the two points:

d= \sqrt{(3-(-6))^2+(2-(-4))^2}

d= \sqrt{(9)^2+(6)^2}

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If the distance from the center to the edge of the circle is the square root of 117, then r^2 = 117.

The answer is:

(x-3)^2+(y-2)^2=117
6 0
3 years ago
Dr. Pagels is a mammalogist who studies meadow and common voles. He frequently traps the moles and has noticed what appears to b
Alina [70]

Answer:

Null hypothesis = H₀ = There food preferences among vole species are independent of one another.

Alternate hypothesis = H₁ = There is a relationship between voles and food preference.

Expected meadow vole/apple slices = 29.983051

Expected common vole/apple slices = 28.016949

Expected meadow vole/peanut butter-oatmeal = 31.016949

Expected common vole/peanut butter-oatmeal = 28.983051

Chi-square value = χ² = 2.154239

Degree of freedom = 1

Critical value = 3.841

χ² < Critical value

We failed to reject H₀

We do not have significant evidence at the given significance level to show that there is a relationship between voles and food preference.

Step-by-step explanation:

He frequently traps the moles and has noticed what appears to be a preference for a peanut butter-oatmeal mixture by the meadow voles vs apple slices are usually used in traps, where the common voles seem to prefer the apple slices.

So he conducted a study where he used a peanut butter-oatmeal mixture in half the traps and the normal apple slices in his remaining traps to see if there was a food preference between the two different voles.

Null hypothesis = H₀ = There food preferences among vole species are independent of one another.

Alternate hypothesis = H₁ = There is a relationship between voles and food preference.

Data collected by Dr. Pagels:

                                              meadow voles     common voles      Row Total

apple slices                                     26                          32                      58

peanut butter-oatmeal                   35                          25                     60

Column Total                                   61                          57                     118

Where 118 is the grand total.

The expected number is given by

Expected = (row total)×(column total)/grand total

Expected meadow vole/apple slices = 58×61/118

Expected meadow vole/apple slices = 29.983051

Expected common vole/apple slices = 58×57/118

Expected common vole/apple slices = 28.016949

Expected meadow vole/peanut butter-oatmeal = 60×61/118

Expected meadow vole/peanut butter-oatmeal = 31.016949

Expected common vole/peanut butter-oatmeal = 60×57/118

Expected common vole/peanut butter-oatmeal = 28.983051

The chi-square statistic value is given by

χ² = Σ(Observed - Expected)²/Expected

χ² = (26 - 29.983051)²/29.983051 + (32 - 28.016949)²/28.016949 + (35 - 31.016949)²/31.016949 + (25 - 28.983051)²/28.983051

χ² = 2.154239

The degrees of freedom is given by

DoF = (row - 1)×(col - 1)

For the given case, we have 2 rows and 2 columns

DoF = (2 - 1)×(2 - 1)

DoF = 1

The given level of significance = 0.05

The critical value from the chi-square table at α = 0.05 and DoF = 1 is found to be

Critical value = 3.841

Conclusion:

Reject H₀ If χ² > Critical value

We reject the Null hypothesis If the calculated chi-square value is more than the critical value.

For the given case,

χ² < Critical value

We failed to reject H₀

We do not have significant evidence at the given significance level to show that there is a relationship between voles and food preference.

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3 years ago
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ohaa [14]

Answer:

D

Step-by-step explanation:

When taking an esponent to an exponent multiply them

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6 0
3 years ago
Rose has $426.00 in her checking account. 1⁄3 of her money will go toward bills. How
Alex Ar [27]

Answer:

<em>$284</em>

Step-by-step explanation:

First,<em> find 1/3 of 426 by multiplying 1/3*426</em>

With your answer <em>(142)</em>, subtract that from the total in your checking account.

<em>426-142=284</em>

This means, After withdrawing the amount she will use to pay bills, Her left over total will be <em>284 dollars.</em>

8 0
3 years ago
Read 2 more answers
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