We can assign variables to each side:
x = first side
y = second side
z = third side
We will assume the "one side" that is greater than the second side is the first side. Since it is "2 times the second side" we can write this as:
x = 2y
Since the third side is 5ft longer than the second side, we can write this as:
y + 5 = z
Perimeter of the triangle (49ft):
x + y + z = 49
We can substitute everything we know.
(2y) + y + (y + 5) = 49
4y + 5 = 49
4y = 44
y = 11
Now we can solve for the other sides with what we have for y.
x = 2(11)
x = 22
11 + 5 = z
16 = z
Add to check.
22 + 11 + 16
33 + 16
49
Therefore, the side lengths are [ 22, 11, and 16 ]
Best of Luck!
5 * 1/4
5/1 * 1/4
5/4
The expression results in an improper fraction.
substituting the value of x and y in the eqn,
3×-2 - ( 4×-2 + 6×3 )
-6 - (-8 + 18 )
-6 - 10
■ -16
Answer:
10 > v (if you don't trust me, check it yourself. Subsitute v for 10 in the first equation.
Step-by-step explanation:
1) 7 > v - 3
2) add 3 to both sides
3) so 7 plus 3 equals 10
So you basically do this
7 > v - 3 (ad 3 to both sides)
You get 10 > v (which is as simplified as possible)
Hope this helps! :)
Answer:
its tb=tc g
Step-by-step explanation: