Answer:
Step-by-step explanation:
Given:
for x≤1400; N = 5
So, Δx = =∑C(a + nΔx).Δx
=C(0)Δx + C(280)Δx + C(560)Δx + C(840)Δx + C(1120)Δx
= Δx[C(0) + C(280) + C(560) + C(840) + C(1120)]
= 280[49 + 42.616 + 34.664 + 25.144 + 14.056]
=280[165.48]
=46334 approx
101 with a remainder of 12
Product = multiply
(6x-y)*(2x-y+2) =
12x^2 -8xy + 12x + y^2 - 2y
2/3 ÷ 4 = 2/3 * 1/4 = 2/12 = 1/6