Question

30 points 1 question PLEASE HELP ME OUT I REALLY NEED IT

Answer 1

Answer:

p(-5/3) ≠  0 So, (3 x +5) is NOT A FACTOR of p(x)

Step-by-step explanation:

Here, the given function is $p(x)=3x^5+2x^2 - 5$

Now, the given root of the function is ( 3x +5)

Now, if ( 3 x +  5) = 0,

we get x = - 5/3

So, the zero of the given polynomial is x = -5/3

Then,  x = -5/3, p(x)  =0 ⇒   ( 3 x + 5) is a FACTOR of p(x)

Now, let us find the value of function at x = -5/3

Substitute x = -5/3 in the given function p(x), we get:

$p(x)=3x^5+2x^2 - 5 \implies p(\frac{-5}{3}) = 3(\frac{-5}{3})^5 + 2(\frac{-5}{3})^2 - 5\\= 3(\frac{-3,125}{243}) + 2(\frac{25}{9}) - 5\\= (\frac{-3,125}{81}) + (\frac{50}{9}) - 5\\= -38.580 + 5.56 - 5 = -38.02\\\implies p(\frac{-5}{3}) = -38.02$

Now, as p(-5/3) ≠  0 So, (3x +5) is NOT A FACTOR of p(x)