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3 years ago

30 points 1 question PLEASE HELP ME OUT I REALLY NEED IT

Mathematics

1 answer:

Pachacha [2.7K]3 years ago

6 0

Answer:

p(-5/3) ≠ 0 So, (3 x +5) is NOT A FACTOR of p(x)

Step-by-step explanation:

Here, the given function is $p(x)=3x^5+2x^2 - 5$

Now, the given root of the function is ( 3x +5)

Now, if ( 3 x + 5) = 0,

we get x = - 5/3

So, the zero of the given polynomial is x = -5/3

Then, x = -5/3, p(x) =0 ⇒ ( 3 x + 5) is a FACTOR of p(x)

Now, let us find the value of function at x = -5/3

Substitute x = -5/3 in the given function p(x), we get:

$p(x)=3x^5+2x^2 - 5 \implies p(\frac{-5}{3}) = 3(\frac{-5}{3})^5 + 2(\frac{-5}{3})^2 - 5\\= 3(\frac{-3,125}{243}) + 2(\frac{25}{9}) - 5\\= (\frac{-3,125}{81}) + (\frac{50}{9}) - 5\\= -38.580 + 5.56 - 5 = -38.02\\\implies p(\frac{-5}{3}) = -38.02$

Now, as p(-5/3) ≠ 0 So, (3x +5) is NOT A FACTOR of p(x)

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Gelneren [198K]

Volume= a³
a=edge
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8 0

3 years ago

Help with #15 please

jonny [76]

Answer:

3 gallons of carpet shampoo

Step-by-step explanation:

room area: 16 * 15 = 240 ft

1 gallon carpet shampoo: 80 ft

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6 0

3 years ago

An automobile manufacturer would like to know what proportion of its customers are not satisfied with the service provided by th

monitta

Answer:

a) n =1623

b) $ME=2.0538\sqrt{\frac{0.21 (1-0.21)}{1623}}=0.0208$

Step-by-step explanation:

1) Notation and definitions

$n$ random sample taken

$\hat p=0.19$ estimated proportion of customers are not satisfied with the service provided by the local dealer

Confidence =0.96 or 96%

Me= 0.02 represent the margin of error

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Part a

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 96% of confidence, our significance level would be given by $\alpha=1-0.96=0.04$ and $\alpha/2 =0.02$ . And the critical value would be given by: