For this case we have the following functions:

We must find
when
.
So:

We apply distributive property to the terms within parentheses taking into account that:

We add similar terms taking into account that different signs are subtracted and the sign of the major is placed:

Thus, we have to:

Then, with x = 2:

Equal signs are added and the same sign is placed.
Answer:

The answer is 2,800 or 2800
The greatest common factor is the largest factor that both terms share.
First, start with the coefficients, 14 and 28. The largest factor they both share is 14. 14 x 1 = 14, 14 x 2 = 28.
Next we move to the variables, abc and a²b²c³. The largest factor the both share is abc, all to the power of 1.
So, your GCF and final answer is 14abc
Answer:The value of the expression increases as r decreases.
Step-by-step explanation:
To find : What happens to the value of the expression as r decreases?
Given Expression: 80-2r
We check for different value of r as decreasing order,
r 80-2r
5 80-10=70
4 80-8=72
3 80-6=74
2 80-4=76
1 80-2=78
As r decreases the value of expression increases.
Therefore, the value of the expression increases as r decreases.
Hope this helps!