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sveta [45]
2 years ago
6

Select the correct comparison Pls help

Mathematics
2 answers:
ruslelena [56]2 years ago
5 0

Answer:

c

Step-by-step explanation:

in set be most of the dots are spread out whereas in set a the points are more bunched up

maria [59]2 years ago
4 0

Answer:

C

Step-by-step explanation:

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7 is to 34 as 5 is to
Katen [24]

Answer:

43

Step-by-step explanation: Ive took the test :)

5 0
3 years ago
X+6/2 - x-8/3 = 5<br><br> HELP PLEASE
Hoochie [10]
(x + 6)/2 - (x - 8)/3 = 5
Multiply each term by 6:-
3(x + 6) - 2(x - 8) = 30
3x + 18 - 2x + 16 = 30
3x - 2x = 30 -18 - 16
x = 30 - 34
x = -4 (answer)
4 0
3 years ago
Read 2 more answers
How much money will you have if you started with $1200 and put it in an account that earned 7.3% every year for 10 years?
andrezito [222]
So an exponential equation is gonna be used for this problem. The formula for such is y=ab^x , in which the a variable is the initial value and the b variable is the growth/decay rate.

For this situation, 1200 is gonna be your a variable since you've started out with it. And as for your b variable, its gonna be 107.3%, or 1.073, since it's increasing.

Your equation should look like this: y=1200(1.073)^x and from here just plug in 10 into the x variable and solve.

Multiply (1.073)^10 (don't round answers until the end), and take that answer and multiply it with 1200, your answer should be $2427.61.

y=1200(1.073)^{10} \\ y=2427.61
8 0
3 years ago
The College Board SAT college entrance exam consists of three parts: math, writing and critical reading (The World Almanac 2012)
Wittaler [7]

Answer:

Yes, there is a difference between the population mean for the math scores and the population mean for the writing scores.

Test Statistics =   \frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } } follows t_n_-  _1 .

Step-by-step explanation:

We are provided with the sample data showing the math and writing scores for a sample of twelve students who took the SAT ;

Let A = Math Scores ,B = Writing Scores  and D = difference between both

So, \mu_A = Population mean for the math scores

       \mu_B = Population mean for the writing scores

 Let \mu_D = Difference between the population mean for the math scores and the population mean for the writing scores.

            <em>  Null Hypothesis, </em>H_0<em> : </em>\mu_A = \mu_B<em>     or   </em>\mu_D<em> = 0 </em>

<em>      Alternate Hypothesis, </em>H_1<em> : </em>\mu_A \neq  \mu_B<em>      or   </em>\mu_D \neq<em> 0</em>

Hence, Test Statistics used here will be;

            \frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } } follows t_n_-  _1    where, Dbar = Bbar - Abar

                                                               s_D = \sqrt{\frac{\sum D_i^{2}-n*(Dbar)^{2}}{n-1}}

                                                               n = 12

Student        Math scores (A)          Writing scores (B)         D = B - A

     1                      540                            474                                   -66

     2                      432                           380                                    -52  

     3                      528                           463                                    -65

     4                       574                          612                                      38

     5                       448                          420                                    -28

     6                       502                          526                                    24

     7                       480                           430                                     -50

     8                       499                           459                                   -40

     9                       610                            615                                       5

     10                      572                           541                                      -31

     11                       390                           335                                     -55

     12                      593                           613                                       20  

Now Dbar = Bbar - Abar = 489 - 514 = -25

 Bbar = \frac{\sum B_i}{n} = \frac{474+380+463+612+420+526+430+459+615+541+335+613}{12}  = 489

 Abar =  \frac{\sum A_i}{n} = \frac{540+432+528+574+448+502+480+499+610+572+390+593}{12} = 514

 ∑D_i^{2} = 22600     and  s_D = \sqrt{\frac{\sum D_i^{2}-n*(Dbar)^{2}}{n-1}} = \sqrt{\frac{22600 - 12*(-25)^{2} }{12-1} } = 37.05

So, Test statistics =   \frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } } follows t_n_-  _1

                            = \frac{-25 - 0}{\frac{37.05}{\sqrt{12} } } follows t_1_1   = -2.34

<em>Now at 5% level of significance our t table is giving critical values of -2.201 and 2.201 for two tail test. Since our test statistics doesn't fall between these two values as it is less than -2.201 so we have sufficient evidence to reject null hypothesis as our test statistics fall in the rejection region .</em>

Therefore, we conclude that there is a difference between the population mean for the math scores and the population mean for the writing scores.

8 0
3 years ago
Solve inequality -8x &lt; 32
castortr0y [4]

Answer:

x > -4

Step-by-step explanation:

I just looked it up

But I know this is it

3 0
3 years ago
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