3 years ago

Can the statement be written as a biconditional statement and why?????

1 answer:

5 0

No. Writing it as a biconditional would mean that "If a number is odd, then it is a prime number" is also true. The original statement is true, but the converse is false.

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How to solve X^4-19x^2+48=0

ZanzabumX [31]

Two numbers that add up to -19 and multiply to 48 are -16 and -3:

$(x^4-19x^2+48)=0\\(x^2-16)(x^2-3)=0\\(x+4)(x-4)(x^2-3)=0$

So, the solutions come from each parentheses: x+4=0, x-4=0, and x^2-3=0.

x+4=0
x = -4

x-4=0
x = 4

x^2-3=0
x^2 = 3
x = +/- √3

So, the solutions are -4, -√3, √3, and 4.

4 0

3 years ago

I would like some assistance pls

nasty-shy [4]

Answer:

where the x axis are you put Your numbers

7 0

3 years ago

Which statements are true of the graph of h(x) = 3/4-4? Check all that apply.

Dmitriy789 [7]

Answer:

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