Question

What is the equation of a circle whose radius is 16 units and center is at (2,-5)?

Answer 1

Answer:

• The general equation of the circle is
• $( {x - a})^{2} + ({y - b})^{2} = {r}^{2} \\ therefore \: we \: \: have \: \\ ( {x - 2})^{2} + (y - ( - 5)) {}^{2} = ({16})^{2} \\ ({x - 2})^{2} + ( {y + 5})^{2} = 256$
• HOPE THIS HELPS!