All categories

4 years ago

If the function f is defined by f(x) = 3x+ 4 then 2f(x) + 4 =?

Mathematics

1 answer:

inessss [21]4 years ago

4 0

2f(x) + 4 = 2(3x + 4) +4

Use the property
a(b+c) = ab + ac

2(3x+4) +4 = 2(3x) + 2(4) + 4
= 6x + 8 + 4
= 6x+ 12

You might be interested in

Consider the graph below, and identify the piecewise function that describes it. An image of a graph. Question 12 options: f(x)=

serious [3.7K]

Answer:

20000

Step-by-step explanation:

HOPED THIS HELPED

A brainlyist is always appreciated

GOOD LUCK

6 0

3 years ago

Which choice is the solution to the inequality below?

irinina [24]

Option B:

The solution to the given inequality is x ≤ 8.

Solution:

Step 1: Given expression is the inequality.

9x ≤ 72

Step 2: To find the solution to the inequality:

9x ≤ 72

Step 3: Divide by 9 on both sides of the inequality.

$$\frac{9x}{9}\leq \frac{72}{9}$

Step 4: The solution is x ≤ 8

The solution to the given inequality is x ≤ 8.

Hence Option B is the correct answer.

4 0

4 years ago

Simply (tan^2 x - sec^2 x)(sin^2 x + cos^2 x)

kati45 [8]

we can use pythagorean identieis

remember that $sin^2(x)+cos^2(x)=1$

also remember that $tan(x)=\frac{sin(x)}{cos{x}}$ and $sec(x)=\frac{1}{cos(x)}$

so if we take $sin^2(x)+cos^2(x)=1$ and divide both sides by $cos^2(x)$ we get

$\frac{sin^2(x)}{cos^2(x)}+\frac{cos^2(x)}{cos^2(x)}=\frac{1}{cos^2(x)}$

$(\frac{sin(x)}{cos(x)})^2+1=(\frac{1}{cos(x)})^2$

$tan^2(x)+1=sec^2(x)$

subtracting $1+sec^2(x)$ from both sides

$tan^2(x)-sec^2(x)=-1$

now subsitute into original problem

$\frac{tan^2(x)-sec^2(x)}{sin^2(x)+cos^2(x)}=$

$\frac{-1}{1}=$

$-1$

the answer is -1

6 0

3 years ago

Whats 107 over 1000 as a decimal

ivann1987 [24]

Step-by-step explanation:

107 / 1000 = 0.107

6 0

3 years ago

Read 2 more answers

Last year, 9 employees of an electronics company retired. Their ages at retirement are listed below

Cloud [144]

Hey, I just wanted to inform you that the ages of the 9 retired employees are not listed anywhere. Hope this can be resolved.

6 0

4 years ago