Answer:
120 degrees and 330 degrees
Step-by-step explanation:
Solve each equation for 0 degrees < x < 360 degrees.
Sqrt 2 cos x + 1 = 0
A.45,315
B.115,245
C.135,225
D.46, 314
Please Help ASAP!
Given the expression √(2cosx+1) = 0
Square both sides of the equation;
√(2cosx+1) = 0
2cosx + 1 = 0
2cosx = -1
cos x = -1/2
x = cos^-1(-1/2)
x = -60 degrees
Since cos is negative in the 2nd and 3rd quadrant then;
x = 180-60 = 120 degrees (2nd quadrant)
x = 270+60 = 330 degrees (3rd quadrant)
Answer:
3x + 5y = -2 is x=
−5
/3
y+
−2
/3
2x - y = 3 is x=
1
/2
y+
3
/2
Step-by-step explanation:
Answer:
B. No the ordered pair does not satisfy the equation
Step-by-step explanation:
y = -9x - 2
Substitute the point in and see if it is true
-37 = -9(4) -2
-37 = -36 -2
-37 = -38
This is not true so the point is not a solution
Answer:
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