3 years ago

Number of operations I need help with understanding it

Mathematics

2 answers:

inessss [21]3 years ago

6 0

Answer:

The four operations are addition, subtraction, multiplication and division!!

Step-by-step explanation:

PtichkaEL [24]3 years ago

5 0

The abs were would be the four operations are addition, subtraction,multiplication and division

You might be interested in

Help plz I’m not good at this

Natalka [10]

Answer:

The correct answer is A. 1/8

Step-by-step explanation:

Let's solve (1/3 * 9/16) / 1 1/2 = x

(1/3 * 9/16) / 1 1/2 = x

9/48 / 1 1/2 = 9/48 * 2/3 = 18/144

18/144, we can simplify dividing by 18 at the numerator and the denominator, this way:

x = 18 ÷ 18/ 144 * 18 = 1/8

The correct answer is A. 1/8

4 0

3 years ago

If A and B are independent events with P(A) = .5 and P(B) = .2, find the following:a) P(A U B)b) P(A^c ? B^c)c) P(A^c U B^c)**No

Effectus [21]

If A and B are independent, then $P(A\cap B)=P(A)P(B)$ .

$P(A\cup B)=P(A)+P(B)-P(A\cap B)=P(A)+P(B)-P(A)P(B)$

$P(A\cup B)=0.5+0.2-0.5\cdot0.2$

$\boxed{P(A\cup B)=0.6}$

b. I'm guessing the ? is supposed to stand for intersection. We can use DeMorgan's law for complements here:

$P(A^c\cap B^c)=P(A\cup B)^c=1-P(A\cup B)$

$P(A^c\cap B^c)=1-0.6$

$\boxed{P(A^c\cap B^c)=0.4}$

c. DeMorgan's law can be used here too:

$P(A^c\cup B^c)=P(A\cap B)^c=1-P(A\cap B)=1-P(A)P(B)$

$P(A^c\cup B^c)=1-0.5\cdot0.2$

$\boxed{P(A^c\cup B^c)=0.9}$

4 0

3 years ago

5x 20 and the. multiplicative inverse of 5

ehidna [41]

That is 5*20 is 100 and the inverse of 5 is 25

8 0

3 years ago

Let x^2 + 11x = 3

Serggg [28]

I hope this helps you

x^2+11x+x+36=39+x

x^2+12x+36=39+x

(x+6)^2=39+x

6 0

3 years ago

Read 2 more answers

Solve the equation: 6x - 8 = 2 + 9x - 1 A. 4 B. -6 C. -2 D. -3

madreJ [45]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers