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4 years ago

1 kilogram= 2.2 pounds, 1 stone= 14 pounds change 42 kilograms into stones

Mathematics

1 answer:

Alex777 [14]4 years ago

7 0

Answer:

6.6 stone

Step-by-step explanation:

We will use conversions to change kilograms to stones

1 kilogram= 2.2 pounds,

1 stone= 14 pounds

42 kilogram 2.2 lbs 1 stone

--------------- * ------------- * ---------------

1 kg 14 lbs

All the units cancel except stone

(42*2.2)/14 stone

6.6 stone

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nataly862011 [7]

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3 years ago

You need to rent a video camera for your school project. Murphy's Camera charges a $30 rental fee plus $35 per day. Allied Renta

andreev551 [17]

A. If a camera is rented for 1 or 2 days, it would be logical to rent it from Murphy's.

B. If a camera is needed for more than 3 days, it would make sense to rent it from Allied rental.

C. Yes, if a camera is rented for 3 days both rentals charge the same money.

C. If you were need a camera for 3 days, you would have to pay $135 for both stores.

Step-by-step explanation:

Step 1; Murphy's camera costs $30 to rent and an additional $35 for each day of rental. So the equations are

y = $30 + (x × $35), where y is total cost and x is the number of days rented.

So for x = 1, y = $30 + (1 × $35) = $30 + $35 = $65

So for x = 2, y = $30 + (2 × $35) = $30 + $70 = $100

So for x = 3, y = $30 + (3 × $35) = $30 + $105 = $135

So for x = 4, y = $30 + (4 × $35) = $30 + $140 = $170

So for x = 5, y = $30 + (5 × $35) = $30 + $175 = $ 205.

Step 2; Allied rental costs $45 to rent and a $30 for each day of rental. So the equations are as follows

y = $45 + (x × $30), where y is total cost and x is the days rented

So for x = 1, $45 + (1 × $30) = $45 + $30 = $75

So for x = 2, $45 + (2 × $30) = $45 + $60 = $105

So for x = 3, $45 + (3 × $30) = $45 + $90 = $135

So for x = 4, $45 + (4 × $30) = $45 + $120 = $165

So for x = 5, $45 + (5 × $30) = $45 + $150 = $195

Step 3; Comparing both prices over 5 days. Murphy's is cheaper for until 2 days. On day 3 both the rentals cost the same but after day 4, allied rentals is the better option.

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3 years ago

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2 years ago

Read 2 more answers

Evaluate the integral

Kruka [31]

Hello, please consider the following.

$\displaystyle \begin{aligned} \int\limits^x {5sin(5t)sin(t)} \, dt &= -\int\limits^x {5sin(5t)} \, d(cos(t))\\ \\&=-[5sin(5t)cos(t)]+ \int\limits^x {25cos(5t)cos(t)} \, dt\\\\&=-5sin(5x)cos(x)+ \int\limits^x {25cos(5t)} \, d(sin(t))\\ \\&=-5sin(5x)cos(x)+[25cos(5t)sin(t)]+ \int\limits^x {25sin(5t)sin(t)} \, dt\\\\&=-5sin(5x)cos(x)+25cos(5x)sin(x)+ \int\limits^x {(25*5)sin(5t)sin(t)} \, dt\end{aligned}$

And we can recognise the same integral, so.

$\displaystyle (25-1)\int\limits^x {5sin(5t)sin(t)} \, dt= +5sin(5x)cos(x)-25cos(5x)sin(x)$

And then,

$\displaystyle \Large \boxed{\sf \bf\int\limits^x {5sin(5t)sin(t)} \, dt=\dfrac{5sin(5x)cos(x)-25cos(5x)sin(x)}{24}+C}$

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3 years ago

A leading magazine (like Barron's) reported at one time that the average number of weeks an individual is unemployed is 33.9 wee

MArishka [77]

Answer:

P(35.3 < M < 35.4) = 0.0040.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sample means with size n of at least 30 can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$