Question

Find the perimeter of triangle ABC.

Answer 1

Answer:

the correct answer is the second (b) choice

9rad2 + rad82

i just took the test and got it right

Answer 2

By definition, the perimeter of the triangle is the sum of its sides.
 We must then use the formula of distance between points:
 $d = \sqrt{(x2-x1) ^ 2 + (y2-y1) ^ 2}$
 We now look for the longitus for each of the sides:
 
 For L1:
 $L1 = \sqrt{(6-2)^2 + (6-2)^2}$
 $L1 = \sqrt{32}$
 $L1 = 4\sqrt{2}$

 For L2:
 $L2 = \sqrt{(7-2)^2 + (-3-2)^2}$
 $L2 = \sqrt{50}$
 $L2 = 5\sqrt{2}$

 For L3:
 $L3 = \sqrt{(7-6)^2 + (-3-6)^2}$
 $L3 = \sqrt{82}$
 
 Then, the perimeter is given by:
 P = L1 + L2 + L3
 Substituting values we have:
 $P = 4\sqrt{2} + 5\sqrt{2} + \sqrt{82} P = 9\sqrt{2} + \sqrt{82}$

 Answer:
 the perimeter of triangle ABC is:
 none of the above.