The owners of an amusement park want to add more rides and an arcade in an open field.Beloe is a sketch of their plan. the owner
s do not know all of the measurements of the field
1 answer:
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Answer:
4) 6x
5) 2x +3
Step-by-step explanation:
We can work both these problems at once by finding an applicable rule.
where O(h²) is the series of terms involving h² and higher powers. When divided by h, each term has h as a multiplier, so the series sums to zero when h approaches zero. Of course, if n < 2, there are no O(h²) terms in the expansion, so that can be ignored.
This can be referred to as the <em>power rule</em>.
Note that for the quadratic f(x) = ax^2 +bx +c, the limit of the sum is the sum of the limits, so this applies to the terms individually:
lim[h→0](f(x+h)-f(x))/h = 2ax +b
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4. The gradient of 3x^2 is 3(2)x^(2-1) = 6x.
5. The gradient of x^2 +3x +1 is 2x +3.
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If you need to "show work" for these problems individually, use the appropriate values for 'a' and 'n' in the above derivation of the power rule.
We want to determine the domain of 
any function of the form
is called an "exponential function",
the only condition is that b is positive and different from 1, and a is a nonzero real number.
The domain of such functions is all real numbers.
That is for any x, the expression <span>3(2^-x) "makes sense".
Answer: </span><span>The domain is all real numbers</span>
any function of the form
the only condition is that b is positive and different from 1, and a is a nonzero real number.
The domain of such functions is all real numbers.
That is for any x, the expression <span>3(2^-x) "makes sense".
Answer: </span><span>The domain is all real numbers</span>
Answer:
If both sides are integers, one side will be 4 feet and the other will be 6 feet. The other solution is the symmetrical solution (4 feet instead of 6 feet, and 6 feet instead of 4 feet).
Step-by-step explanation:
We have a rectangular blanket, that has a diagonal that measures h=7.21 feet.
The two sides of the rectangle a and b can be related to the diagonal h by the Pithagorean theorem:
Then, we can express one side in function of the other as:
Then, if we define b, we get the value of a that satisfies the equation.
A graph of values of a and b is attached.
If both side a and b are integers, we can see in the graph that are only two solutions: (b=4, a=6) and (a=4, b=6).
