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viva [34]
3 years ago
10

Which relation is a function of x? 1 {(1,2), (7, 6), (3, 2), (1, 0), (5, 6)}. 3. x=3y²–7

Mathematics
1 answer:
avanturin [10]3 years ago
4 0

9514 1404 393

Answer:

  The given graph shows a function of x.

Step-by-step explanation:

Neither 1 nor 3 is a single-valued relation for some values of x. The graph shown passes the vertical line test, so does represent a function.

The graph is a relation that is a function of x.

___

The attached graph is of the equation of 3. A vertical line will intersect the graph in more than one place, so the relation is NOT a function.

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The value of y is directly proportional to the value of x If y=81 when x=54, what is the value of y when x=38
Arisa [49]

Answer:

y = 57

Step-by-step explanation:

y α x

y = kx ; k = Constant of proportionality

81 = k* 54

k = 81/54

k = 1.5

Value of y when x = 38

y = kx

y = 1.5 * 38

y = 57

Hence, y = 57 when x = 38

5 0
3 years ago
The population of Town A increases by 5% every year. Its current population is 700,000. Town B, which currently has 550,000 resi
gladu [14]

Answer:

1,260

Step-by-step explanation:


5 0
3 years ago
Is 2.3 bigger than 2.38
il63 [147K]
No, 2.3 is not bigger than 2.38.

In fact, 2.30 is less than 2.38.
4 0
3 years ago
Read 2 more answers
Write an equation of the line in slope-intercept form that passes through (-3,5) and is perpendicular to y = -3x- 1
inna [77]

9514 1404 393

Answer:

  y = 1/3x +6

Step-by-step explanation:

The slope of the given line is the coefficient of x, -3. The slope of the perpendicular line will be the opposite reciprocal of that:

  -1/(-3) = 1/3

The point-slope equation is then ...

  y -k = m(x -h) . . . . . for line of slope m through point (h, k)

Here, we have m = 1/3, (h, k) = (-3, 5), so the point-slope equation is ...

  y -5 = 1/3(x +3)

  y = 1/3x + 1 + 5 . . . . eliminate parentheses, add 5

  y = 1/3x +6 . . . . slope-intercept equation of the line

6 0
3 years ago
The number of chocolate chips in a bag of chocolate chip cookies is approximately normally distributed with mean 1263 and a stan
DENIUS [597]

Answer:

(a) The 29th percentile for the number of chocolate chips in a bag is 1198.65.

(b) The number of chocolate chips in a bag that make up the middle 95​% of bags are [1146, 1380].

(c) The inter-quartile range of the number of chocolate chips in a bag of chocolate chip​ cookies is 157.83.

Step-by-step explanation:

Let the random variable <em>X</em> represent the number of chocolate chips in a bag of chocolate chip cookies.

The random variable <em>X</em> is normally distributed with mean, <em>μ </em>= 1263 and a standard deviation, <em>σ </em>= 117.

(a)

Compute the 29th percentile for the number of chocolate chips in a bag as follows:

P (X < x) = 0.29

⇒ P (Z < z) = 0.29

The value of <em>z</em> for the above probability is, <em>z</em> = -0.55.

Compute the value of <em>x</em> as follows:

z=\frac{x-\mu}{\sogma}\\-0.55=\frac{x-1263}{117}\\x=1263-(117\times 0.55)\\x=1198.65

Thus, the 29th percentile for the number of chocolate chips in a bag is 1198.65.

(b)

According to the Empirical rule 95% of the normally distributed data lies within 2 standard deviations of the mean.

P (μ - σ < X < μ + σ) = 0.95

P (1263 - 117 < X < 1263 + 117) = 0.95

P (1146 < X < 1380) = 0.95

Thus, the number of chocolate chips in a bag that make up the middle 95​% of bags are [1146, 1380].

(c)

The inter-quartile range of the normal distribution is:

IQR = 1.349 <em>σ</em>

Compute the inter-quartile range of the number of chocolate chips in a bag of chocolate chip​ cookies as follows:

IQR = 1.349 <em>σ</em>

      = 1.349 × 117

      = 157.833

Thus, the inter-quartile range of the number of chocolate chips in a bag of chocolate chip​ cookies is 157.83.

5 0
3 years ago
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